Answer:
I need the points :((((((
Answer:
Let's pick six liquids randomly, i.e. honey, corn syrup, whole milk, water, vegetable oil, rubbing alcohol, and put them in a beaker. The higher density liquid will take the bottom position whereas lower density liquids will be on above of high density liquids.
We know that honey has density (g/cm3) of 1.42, dish soap has 1.06, corn syrup has 1.33, milk has 1.03, water has 1.00 (standard), and vegetable oil and 0.92. Therefore, honey will be at the bottom most position (rank #1). Above which would be corn syrup (rank #2), dish soap (rank #3), milk (rank #4), water (rank #5) and vegetable oil (rank #6).
The results might be surprising for some students who think that water has highest density.
<span>Both the populations of Drosophila seem to have the same gene for foraging behavior
Therefore, the </span><span>alternative hypothesis which is made far less likely by having three R and K lines, rather than one of each is:
</span><span>The difference between the R and K lines is the result of environmental differences in the food availability of their habitats.
</span>
Answer:
D) Water temperature decreases; copper temperature increases
Explanation:
The temperature is a way of describing how much heat something has. Because the temperatures of the two substances are not the same, the heat is going to want to travel to the substance with less heat. Therefore, since the copper has less heat than the water, the heat will be transferred to the copper. Remember that this heat is now leaving the water. This increases the temperature of the copper and decreases the temperature of the water.
The question is incomplete as it does not have the option which are:
-acid-fast
-DAPI
-lipo
-Gram
Answer:
Acid-fast staining
Explanation:
Acid-fast staining is the technique used to stain and identify the species of the mycobacterium.
During the acid-fast staining, the carbolfuchsin stain is used to color the bacteria as carbolfuchsin solubilizes the lipid of the bacterial wall and the pink stain enters the cell. When these cells are treated with the methylene blue counterstain, the mycobacterium due to the presence of thick cell wall does not allow the entry of the methylene blue as a result of which they appear red o pink.
Thus, acid-fast staining is correct.