The domain is the set of all real numbers.
The range is the set of all real numbers.
Answer:
Numbers =(6,-2 )
Step-by step explanation:
Given
the sum of two numbers is four and the sum of their squares minus three times their product is 76,
Let the first term =X
Second term will be=4-x
So
X^2+(4-x)^2-3x(4-x)=76
x^2+16+x^2-8x-12x+3x^2=76
5x^2-20x+16=76
5x^2-20x-60=0
5(x^2-4x-12)=0
So x^2-4x-12=0
x^2-(6-2)x-12=0
x^2-6x+2x-12=0
X(x-6)+2(x-6)=0
(X-6)(X+2)=0
X=6,-2
Let X=6 and -2 then numbers will be 6 and (4-6)=-2
Tenth place is the answer!! :))
Substitute y=4x to the second equation:
x^2 + (4x)^2 = 17
x^2 + 16x^2 = 17
17x^2 = 17
x^2 = 17/17
x^2 = 1
x = 1 and -1
When x=1, y=4(1) = 4
When x=-1, y=4(-1) = -4
Thus the solutions would be (1,4) and (-1,-4). That would correspond to D. and A.
Answer:
5:1
Step-by-step explanation:
So, we know that 20 fries were large, and 4 were small. So, we just set it up as 20:4 <em>(for every 20 large fries, there are 4 small ones)</em>. However, it needs to be simplified which results in 5:1.
Hope I helped!!