I need help!!!! Please lol

Suppose a < -1. what must be true about the value of b so that ab < a? PLEASE HELP

Zepler [3.9K]

Answer: A, B, and C are positive constants and that x+y= C. Show that the minimum value of +Ax%5E2%2BBy%5E2+ occurs when .

Step-by-step explanation:

;)

6 0

2 years ago

URGENT NEED HELP FAST LINKS WILL BE REPORTED

Butoxors [25]

Answer:

Model B

Step-by-step explanation:

First, solve what each model means:

Model A:

6 boxes, 2 shaded

2/6=1/3

1/3 is approximately 33.35

Model B:

8 boxes, 3 shaded

3/8 is 37.5%

this is the answer, but we can go ahead and check the other boxes

Model C:

5 boxes, 2 shaded

2/5 is 40%

Model D:

7 boxes, 3 shaded

3/7 is approximately 42.9%

Lmk if you have more questions!

5 0

2 years ago

Which lines in the graph have a slope greater than 1 but less than 2?

lapo4ka [179]

Answer:

Lines 3 and 4

Step-by-step explanation:

Let's examine the slope of each of the given lines to have the exact value and be able to answer the question. We use the definition of: $slope=\frac{rise}{run}$

Line 1: $slope=\frac{rise}{run}=\frac{6}{2} = 3$

Line 2: $slope=\frac{rise}{run}=\frac{6}{3} = 2$

Line 3: $slope=\frac{rise}{run}=\frac{6}{4} = 1.5$

Line 4: $slope=\frac{rise}{run}=\frac{6}{5} = 1.2$

Line 5: $slope=\frac{rise}{run}=\frac{6}{6} = 1$

Therefore the lines that have slope strictly greater than 1 and less than 2 are:

Lines 3 and 4

3 0

2 years ago

Read 2 more answers

What is the answer???

Greeley [361]

Answer:

Angles in ascending order:

Q, R, S

Step-by-step explanation:

The side with the biggest number also has the biggest angle degree. The side with the smallest number also has the smallest angle degree.

6 0

2 years ago

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The areas of two similar triangles are 72dm2 and 50dm2. The sum of their perimeters is 226dm. What is the perimeter of each of t

astraxan [27]

Answer:

Hence, the perimeter of the triangles are:

P=123.2727 dm

P'=102.7272 dm

Step-by-step explanation:

In two similar triangles:

The ratio of the areas of two triangle is equal to the square of their perimeters.

Let A and A' represents the area of two triangles and P and P' represents their perimeter.

Then they are related as:

$\dfrac{A}{A'}=\dfrac{P^2}{P'^2}$

We are given:

A=72 dm^2 , A'=50 dm^2

and P+P'=226 dm.-----------(1)

i.e. $\dfrac{72}{50}=\dfrac{P^2}{P'^2}\\\\\dfrac{36}{25}=\dfrac{P^2}{P'^2}$

on taking square root on both the side we get:

$\dfrac{P}{P'}=\dfrac{6}{5}\\\\P=\dfrac{6}{5}P'$

Now putting the value of P in equation (1) we obtain:

$\dfrac{6}{5}P'+P'=226\\\\\dfrac{6P'+5\times P'}{5}=226\\\\\dfrac{6P'+5P'}{5}=226\\\\11P'=226\times 5\\\\11P'=1130\\\\P'=\dfrac{1130}{11}=102.7272$

Hence,

P=226-102.7272=123.2727

Hence, the perimeter of the triangles are:

P=123.2727 dm

P'=102.7272 dm

6 0

2 years ago