Answer:
cot theta = -√3
Step-by-step explanation:
we are given that cos theta = - √3/2 within the range 180° < theta < 270° and
since cos theta = adj/hyp
adj = - √3
hyp = 2
Get the opposite using the pythagoras theorem
hyp^2 = opp^2 + adj^2
2² = opp² + (-√3)²
4 = opp² + 3
opp² = 4-3
opp² = 1
opp = 1
tan theta = opp/adj
tan theta = - 1/√3
Recall that cot theta = 1/tan theta
cot theta = 1/(-1/√3)
cot theta = -√3
Answer:
<u>Please read the answer below.</u>
Step-by-step explanation:
<u>Question 2. 25% of what number is 30?</u>
25% - Whole 30, 50% Whole 60, 75% Whole 90, 100% Whole 120
<u>Question 3. What operation did you use the find the whole?</u>
In the previous question, I found the whole, adding 30 to the previous value.
For example, I added 30 to 30 and calculate 60. To 60 then i added 30 to get 90 and added 30 to get 120 because in this question, all the 4 parts were exactly the same size (30).
<u>Question 4. What are you multiplying/dividing? Do you use the percent or something else?</u>
In the specific case of question 2, I noticed that the size of the parts were exactly the same, using it for calculating the whole. If 1 part out of 4 is 30, then 2 parts or 50% are 60, 3 parts or 75% are 90 and then 4 parts of 100% are the whole I'm being asked, in this case, 120.
1000
Step-by-step explanation:
Let the share of votes obtained by the parties A, B and C be x, 2x and 4x respectively.
According to the given information:
No of votes obtained by C = 1500 + No of votes obtained by A
Answer:
Class Boundary = 1 between the sixth and seventh classes.
Step-by-step explanation:
Lengths (mm) Frequency
1. 140 - 143 1
2. 144 - 147 16
3. 148 - 151 71
4. 152 - 155 108
5. 156 - 159 83
6. 160 - 163 18
7. 164 - 167 3
The class boundary between two classes is the numerical value between the starting value of the higher class, which is 164 for the 7th class in this case, and the ending value of the class of the lower class, which is 163 for the 6th class in this case.
Therefore the class boundary between the sixth and seventh classes
= 164 - 163 = 1
Therefore Class Boundary = 1.
It can be seen that class boundary for the frequency distribution is 1.
If we take the difference between the lower limits of one class and the lower limit of the next class then we will get the class width value.
Therefore, Class width,
w = lower limit of second class - lower limit of first class
= 144 - 140
= 4
Answer:
C abc dm<a=60> o+a ,m(b=60o'a is equal to 150