6y^2-7y-3-2y^2+9y+7 (pretend that you're multiplying -1 to 2y^2-9y-7 which is why 9y and 7 are positive now).
Now you're able to simplify your problem, so...
6y^2-2y^2= 4y^2
-7y+9y= 2y
-3+7=4
4y^2+2y+4
Might want to check my math but that's how you do it.
Answer:
Measure of arc ZWX is <u>230°.</u>
Step-by-step explanation:
Given:
arc WX = 50°
Now
The diameter divide a circle into two equal parts
so
Since WZ is diameter of the circle.
substituting in above equation we get
Hence Measure of arc ZWX is <u>230°.</u>
<u>Given</u>:
Given that FGH is a right triangle. The sine of angle F is 0.53.
We need to determine the cosine of angle H.
<u>Cosine of angle H:</u>
Given that the sine of angle F is 0.53
This can be written as,
Applying the trigonometric ratio, we have;
----- (1)
Now, we shall determine the value of cosine of angle H.
Let us apply the trigonometric ratio , we get;
----- (2)
Substituting the value from equation (1) in equation (2), we get;
Thus, the cosine of angle H is 0.53
Answer:
y = 8/3
Step-by-step explanation:
x = -2
y = 2/(3*-2) + 3
y = 2/-6 + 3
y = -1/3 + 3
y = -1/3 + 9/3
y = 8/3
The quick and easy answer is 3/100