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Answer: </h3><h3>
speed of train A = 44 mph</h3>
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Work Shown:
x = speed of train A
y = speed of train B
"train A travels 4/5 the speed of train B" (I'm assuming "train one" is supposed to read "train B"). So this means x = (4/5)y
distance = rate*time
d = x*7
d = (4/5)y*7 = (28/5)y represents the distance train A travels
d = y*7 = 7y represents the distance train B travels
summing those distances will give us 693
(28/5)y + 7y = 693
5*( (28/5)y + 7y ) = 5*693
28y + 35y = 3465
63y = 3465
y = 3465/63
y = 55
Train B's speed is 55 mph
4/5 of that is (4/5)y = (4/5)*55 = 4*11 = 44 mph
Train A's speed is 44 mph
Answer:
Step-by-step explanation:
Ok so for the first one it’s super simple I’m gonna do it as less complicated so it can help you :)
So first we need to convert the mixed number to an improper fraction
1 4/5 = 9/5
Now we need to reduce the numbers greatest common divisor which is 3
3/5 x 6
Now multiply the numbers
Your answer is 18/5 I hoped this help
Now for the second one
this one is a little more complicated and I don’t know how to make it sound easier so I’m gonna tell you the answer which is 580/21
The last one is the same steps we did for the first one which is 27/20
I hoped this helped you it is a little difficult but you’ll get the hang of it :)