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2 years ago

Solve in one variable 2/3x + 5 = 3/2x

1 answer:

Montano1993 [528]2 years ago

5 0

First, we group together the terms with variables in one side by subtracting 3/2 x and 5 from both sides of the equation.
(2/3)x - (3/2)x + 5 - 5 = (3/2)x - (3/2)x - 5
(-5/6)x = -5
The value of x from the equation is 6.

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∠EFG and ∠LMN are supplementary angles, m∠EFG=(3x+17)º, and m∠LMN=(12x−5)º.

Ira Lisetskai [31]

Answer:

EFG = 50.6, LMN = 129.4

Step-by-step explanation:

ok so s supplementary angles mean, their angles will always add upto 180. for example if one angle is 100° then the other will be 80°.

to find the angles first we need to solve for x.

we know EFG + LMN = 180 because its supplementary.

that's is (3x+17) + (12x-5) = 180.

we now solve for x;

15x+12 = 180

15x = 168, x= 168/15 = 11.2

now that we know x we can put this value in the corresponding equation of EFG and LMN to find the angles.

EFG = 3x11.2 + 17 = 50.6

LMN = 12x11.2 - 5 = 129.4

7 0

2 years ago

Find the angle between the given vectors. Round your answer, in degrees, to two decimal places. u=⟨2,−6⟩u=⟨2,−6⟩, v=⟨4,−7⟩

NISA [10]

Answer:

$\theta = 108.29$

Step-by-step explanation:

Given

$u =$

$v =$

Required:

Calculate the angle between u and v

The angle $\theta$ is calculated as thus:

$cos\theta = \frac{u.v}{|u|.|v|}$

For a vector

$A =$

$A = a * b$

$cos\theta = \frac{u.v}{|u|.|v|}$ becomes

$cos\theta = \frac{.}{|u|.|v|}$

$cos\theta = \frac{2*6+4*-7}{|u|.|v|}$

$cos\theta = \frac{12-28}{|u|.|v|}$

$cos\theta = \frac{-16}{|u|.|v|}$

For a vector

$A =$

$|A| = \sqrt{a^2 + b^2}$

So;

$|u| = \sqrt{2^2 + 6^2}$

$|u| = \sqrt{4 + 36}$

$|u| = \sqrt{40}$

$|v| = \sqrt{4^2+(-7)^2}$

$|v| = \sqrt{16+49}$

$|v| = \sqrt{65}$

So:

$cos\theta = \frac{-16}{|u|.|v|}$

$cos\theta = \frac{-16}{\sqrt{40}*\sqrt{65}}$

$cos\theta = \frac{-16}{\sqrt{2600}}$

$cos\theta = \frac{-16}{\sqrt{100*26}}$

$cos\theta = \frac{-16}{10\sqrt{26}}$

$cos\theta = \frac{-8}{5\sqrt{26}}$

Take arccos of both sides

$\theta = cos^{-1}(\frac{-8}{5\sqrt{26}})$

$\theta = cos^{-1}(\frac{-8}{5 * 5.0990})$

$\theta = cos^{-1}(\frac{-8}{25.495})$

$\theta = cos^{-1}(-0.31378701706)$

$\theta = 108.288386087$

$\theta = 108.29$ (approximated)

4 0

1 year ago

Zuri quickly solved the problem and told her team, "Hey! I go it m\large \angleA = 93°, m\large \angleB = 63°, m\large \angleC =

Step2247 [10]

Answer:

Mikaya and Olivia are correct to be suspicious

Step-by-step explanation:

Sum of the angles of a triangle is always 180

But, The sum of all angles of the triangle that Zuri solved = 93 + 63 + 36 = 192 ≠ 180

So, Zuri is wrong

8 0

2 years ago

Jason Bourne has been held captive in a prison from which there are three possible routes to escape: an air duct, a sewer pipe a

laila [671]

Answer:

Rx2e-xdx=-e-x(x2+2x+2)+candR-xe-xdx=xe-x+e-x+c)CS 70, Summer 2016, HW 62

Step-by-step explanation:

CIA(8 points)Jason Bourne has been held captive in a prison from which there are three possible routes to escape:an air duct, a sewer pipe and the door (which happens to be unlocked). The air duct leads him on athree hour trip whereupon he falls through a trap door onto his head. The sewer pipe is similar buttakes two hours to traverse. Each fall produces amnesia and he is returned to the cell immediatelyafter each fall. Assume that he always immediately chooses one of the three exits from the cell withprobability13. On average, how long does it take before he opens the unlocked door and escapes?9.Markov Chain(12 points: 4/3/5)Consider the Markov chainX(n)with the state diagram shown below, wherea,b∈(0,1).Figure 1: State diagram(a) Is this Markov chain irreducible? Is it aperiodic? Briefly justify your answers.(b) Calculate Pr[X1=1,X2=0,X3=0,X4=1|X0=0].(c) Calculate the invariant distribution.CS 70, Summer 2016, HW 63

Alice and Bob are going to study for the upcoming midterm together. They agree to meet at timetthis afternoon. Alice will show upXhours aftert, whereX∈Uniform[0,2]. Bob’s arrival time ismore unpredictable. He will be distracted by Pokemon Go and will show upYhours aftert, whereY∈Expo(1). The person who shows up later is late forThours. What isE[T]? (Hint: some usefulintegrals

# if you need any queshtions aswered speedly hit me up and I got you

7 0

2 years ago

A human gene carries a certain disease from the mother to the child with a probability rate of 34%. That is, there is a 34% chan

fenix001 [56]

Answer:

The probability that at least one of the children get the disease from their mother is 0.7125.

Step-by-step explanation:

We are given that a human gene carries a certain disease from the mother to the child with a probability rate of 34%.

Suppose a female carrier of the gene has three children. Assume that the infections of the three children are independent of one another.

Let Probability that children get the disease from their mother = P(A) = 0.34

SO, Complement of the event "At least one of the children get the disease from their mother"= P(A') = 1 - P(A)

where A' = event that children do not get the disease from mother.

So, P(A') = 1 - P(A) = 1 - 0.34 = 0.66

Now, probability that at least one of the children get the disease from their mother = 1 - Probability that none of the three children get disease from their mother

= 1 - P(X = 0)

= 1 - (0.66 $\times$ 0.66 $\times$ 0.66)

= 1 - 0.2875 = 0.7125

7 0

2 years ago