A new Community Sport complex is being built in safe harbor the perimeter of the rectangular playing field is 402 yards the leng
th of the field is 9 yards less than quadruple the width what are the dimensions of the playing field?
1 answer:
Answer:
<h2>length = 159 yards</h2><h2>width = 42 yards</h2>
Step-by-step explanation:
Perimeter of a rectangle = 2l + 2w
where
l is the length
w is the width
From the question
Perimeter = 402 yards
The statement
the length of the field is 9 yards less than quadruple the width is written as
l = 4w - 9
Substitute this is expression into the above formula and solve for the width
That's
402 = 2( 4w - 9) + 2w
402 = 8w - 18 + 2w
10w = 402 + 18
10w = 420
Divide both sides by 10
<h3>w = 42</h3>
Substitute this value into l = 4w - 9
That's
l = 4(42) - 9
l = 168 - 9
<h3>l = 159</h3>
Therefore
length = 159 yards
width = 42 yards
Hope this helps you
You might be interested in
B
Hope this helps helps helps
The answer is c
let’s say he rents it for 2 hours,
t= hours, so t=2
20 is the deposit and since t is multiplied by 8,
8(2) + 20
Yes is equivalent because 12 x 4 is 48 and 5x5 is 25
Answer: D.
Step-by-step explanation: you find the ratio of the other lengths, then apply that ratio to the length of DC. Pls mark as brainliest?
Angle TQS is equal to 74 degrees
