Answer: f(7) = f(4) + 3(3) = 15 + 9 = 24
Step by Step Explanation:
f(1) = 6
f(n) = f(n-1) + 3
f(2) = f(1) + 3 = 6+3 = 9
f(3) = f(2) + 3 = 12
f(4) = f(3) + 3 = 15
Each term is 3 more than the previous one
Therefore to get from the 4th term to the 7th term you will add 3
For a total of 3 more times.
f(7) = f(4) + 3(3) = 15 + 9 = 24
Hope this helps
(Y1-Y2)/(X1-X2)
(2-4)/(-2-3)
-2/-5
2/5
Answer: 5000 cm is greater than 5 m
Step-by-step explanation:
When you convert 5000 cm to m 5000 cm is equal to 50 m so 5000 cm is greater than 5 m
To find f(3), plug x = 3 in f(x),
∴ f(3) = 3(3)+1 = 9+1 = 10
Therefore, the ordered pair is (3,10)
For second one,
plug x = 10 in f⁻¹(x),
f⁻¹(10) = 10-1/3 = 9/3 = 3
Therefore, the ordered pair is (10,3)
Answer:
There can be 14,040,000 different passwords
Step-by-step explanation:
Number of permutations to order 3 letters and 2 numbers (total 5)
(AAANN, AANNA,AANAN,...)
= 5! / (3! 2!)
= 120 / (6*2)
= 10
For each permutation, the three distinct (English) letters can be arranged in
26!/(26-3)! = 26!/23! = 26*25*24 = 15600 ways
For each permutation, the two distinct digits can be arranged in
10!/(10-2)! = 10!/8! = 10*9 = 90 ways.
So the total number of distinct passwords is the product of all three permutations,
N = 10 * 15600 * 90 = 14,040,000