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3 years ago

Trevor sees eight red birds he sees five more red birds then blue birds how many blue birds does Trevor see

Mathematics

1 answer:

horrorfan [7]3 years ago

3 0

Answer:

3 blue birds

Step-by-step explanation:

To answer this question, simply subtract:

8 - 5 = 3

So, Trevor saw 3 blue birds

Hope this helps!

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A positive number is 5 less than 3 times another. The sum of the smaller number and 4 times the larger is 97. Find the smaller n

Gre4nikov [31]

Answer:

Step-by-step explanation:

The first sentence of the problem can be interpreted two ways. The way that makes the second sentence work out correctly is ...

'a larger number is 5 less than 3 times a smaller number'

Using x for the smaller number, the two equations that can be written are ...

3x -y = 5
x +4y = 97

Adding 4 times the first equation to the second, we get ...

4(3x -y) + (x +4y) = 4(5) +(97)

13x = 117 . . . . . simplify

x = 9 . . . . . . . . divide by 13

The smaller number is 9.

5 0

2 years ago

Right now there are 600 everlasting roses in my garden. I want at least 200 roses in the garden at all times. If the gardener cu

Radda [10]

Answer:

Thefore, we conclude that she can have another 16 weeks, more than 200 roses.

Step-by-step explanation:

We know that right now there are 600 everlasting roses in garden. I want at least 200 roses in the garden at all times. If the gardener cutting 25 roses a week to decrote my throne room.

We calculate:

$t=(600-200) : 25\\\\t=400 : 25\\\\t=16\\$

Thefore, we conclude that she can have another 16 weeks, more than 200 roses.

8 0

2 years ago

Read 2 more answers

Rationalize the denominator of $\frac{\sqrt{32}}{\sqrt{16}-\sqrt{2}}$. The answer can be written as $\frac{A\sqrt{B}+C}{D}$, whe

musickatia [10]

Rationalizing the denominator involves exploiting the well-known difference of squares formula,

$a^2-b^2=(a-b)(a+b)$

We have

$(\sqrt{16}-\sqrt2)(\sqrt{16}+\sqrt2)=(\sqrt{16})^2-(\sqrt2)^2=16-2=14$

so that

$\dfrac{\sqrt{32}}{\sqrt{16}-\sqrt2}=\dfrac{\sqrt{32}(\sqrt{16}+\sqrt2)}{14}$

Rewrite 16 and 32 as powers of 2, then simplify:

$\dfrac{\sqrt{32}}{\sqrt{16}-\sqrt2}=\dfrac{\sqrt{2^5}(\sqrt{2^4}+\sqrt2)}{14}$

$\dfrac{\sqrt{32}}{\sqrt{16}-\sqrt2}=\dfrac{2^2\sqrt2(2^2+\sqrt2)}{14}$

$\dfrac{\sqrt{32}}{\sqrt{16}-\sqrt2}=\dfrac{4\sqrt2(4+\sqrt2)}{14}$

$\dfrac{\sqrt{32}}{\sqrt{16}-\sqrt2}=\dfrac{16\sqrt2+4(\sqrt2)^2}{14}$

$\dfrac{\sqrt{32}}{\sqrt{16}-\sqrt2}=\dfrac{16\sqrt2+8}{14}$

$\dfrac{\sqrt{32}}{\sqrt{16}-\sqrt2}=\dfrac{8\sqrt2+4}7$

So we have A = 8, B = 2, C = 4, and D = 7, and thus A + B + C + D = 21.

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2 years ago

Choose the statement that is true.

Andrej [43]

Answer:

The answer is A. If two polygons are congruent, then they are similar

Step-by-step explanation:

Just took the test!

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2 years ago

Which of the following are examples of exponential decay? select all that apply.

Katarina [22]

B, C and D are exponential decay.

Half-lives are given by exponential function, and since they are decreasing, it is decay.
With the teams being eliminated, this is decay.
Bacteria can be represented by exponential functions, and it is decreasing.

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2 years ago