<h2><u>
Answer:</u></h2>
Which ordered pairs are in the solution set of the system of linear inequalities?
y > Negative one-halfx
y < One-halfx + 1
On a coordinate plane, 2 straight lines are shown. The first solid line has a negative slope and goes through (0, 0) and (4, negative 2). Everything above the line is shaded. The second dashed line has a positive slope and goes through (negative 2, 0) and (2, 2). Everything below the line is shaded.
(5, –2), (3, 1), (–4, 2)
(5, –2), (3, –1), (4, –3)
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(5, –2), (3, 1), (4, 2)</u></h2>
(5, –2), (–3, 1), (4, 2)
Step-by-step explanation:
When applying indirect proofs, we assume the negation of the conclusion is true, and show that this assumption would lead to nonsense, or contradiction.
In our case we assume a is not smaller than 7, that is we assume a≥7.
a≥7 then, multiplying both sides by 3:
3a≥21, then, adding both sides 7:
3a+7≥28,
which is a contradiction because 3a+7 is smaller than 28.
So our assumption is wrong, which means the opposite of it is correct.
Answer: assume a≥7
Answer: Not sure but try D
Step-by-step explanation:
not sure
The two numbers are both -15
-15 x -15= 225
-15+ -15= -30
We can use the points (2, -2) and (4, -1) to solve.
Slope formula: y2-y1/x2-x1
= -1-2/4-(-2)
= -3/6
= -1/2
Point slope form: y - y1 = m(x - x1)
y - 2 = -1/2(x + 2)
Solve for y-intercept.
-2 = -1/2(2) + b
-2 = -1 + b
-2 + 1 = -1 + 1 + b
-1 = b
Slope Intercept Form: y = mx + b
y = -1/2x - 1
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Best Regards,
Wolfyy :)