Answer:
Time t = 2 seconds
It will reach the maximum height after 2 seconds
Completed question;
Amir stands on a balcony and throws a ball to his dog who is at ground level. The ball's height, in meters above the ground, after t seconds that Amir has thrown the ball is given by:
H (t) = -(t-2)^2+9
many seconds after being thrown will the ball reach its maximum height?
Step-by-step explanation:
The equation of the height!
h(t) = -(t-2)^2 + 9 = -(t^2 -4t +4) + 9
h(t) = -t^2 +4t -4+9
h(t) = -t^2 + 4t +5
The maximum height is at dh/dt = 0
dh/dt = -2t +4 = 0
2t = 4
t = 4/2 = 2
Time t = 2 seconds
It will reach the maximum height after 2 seconds
Answer:a,c,d
Step-by-step explanation:
52). 5x=45 Divide each side of the equation by 5.
53). -3x = 12 Divide each side by -3.
54). x/4 = 10 Multiply each side by 4 .
55). x/3 = -8 Multiply each side by 3 .
1). x -10 = 12 . Add 10 to each side.
3). x + 8 = 16 Subtract 8 from each side.
5). 5 + x = 6 Subtract 5 from each side.
7). x - 4 = 9 Add 4 to each side.
Thank you for the 5 points. The crust and warm water are delicious.
Answer:
148
Step-by-step explanation:
Sa=2(lw+lh+wh)
Sa=2(4*5+4*6+5*6)
148=2(4*5+4*6+5*6)
