All categories

2 years ago

The mean of four consecutive even numbers is 15. The greatest of these numbers is a1. The least of these numbers is a2.

1 answer:

6 0

X + (x + 2) + ( x + 4) + (x + 6)
-----------------------------------   = 15
   4

4x + 12
--------- = 15
    4

Multiply by 4 on both sides

4x + 12 = 60
subtract 12 from both sides
4x = 48
divide by 4 on each side
x = 12
x + 2 = 14
x + 4 = 16
x + 6 = 18

You might be interested in

Solve 2x2 + 20x = −38. (1 point)

RoseWind [281]

Answer:

The solutions are $x=-5+\sqrt{6}$ and $x=-5-\sqrt{6}$

Step-by-step explanation:

we have

$2x^{2} +20x=-38$

Divide by $2$ both sides

$x^{2} +10x=-19$ ------> $x^{2} +10x+19=0$

we know that

The formula to solve a quadratic equation of the form $ax^{2} +bx+c=0$ is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$x^{2} +10x+19=0$

$a=1\\b=10\\c=19$

substitute

$x=\frac{-10(+/-)\sqrt{10^{2}-4(1)(19)}}{2(1)}$

$x=\frac{-10(+/-)\sqrt{100-76}}{2}$

$x=\frac{-10(+/-)\sqrt{24}}{2}$

$x=\frac{-10(+/-)2\sqrt{6}}{2}$

$x1=\frac{-10(+)2\sqrt{6}}{2}=-5+\sqrt{6}$

$x2=\frac{-10(-)2\sqrt{6}}{2}=-5-\sqrt{6}$

8 0

2 years ago

Read 2 more answers

Find the perimeter and area, to the nearest

vredina [299]

Perimeter is equal to 90 in.

Area is approximately equal to 389.71 in.

3 0

2 years ago

15 - (-3) - 4 -16 22 -8 14

uranmaximum [27]

In this equation, you have to treat the number in the bracket first on the basis of BODMAS
15 - [-3]- 4
Note that when two minuses come together the product is a plus sign.
15 +3 - 4
You have to add before you subract
18 - 4 =14
Therefore, 15- [-3] - 4 = 14.

8 0

3 years ago

would set a new school record? A number line going from 515 to 521. An open circle is at 518. Everything to the left of the circ

Rudik [331]

Answer:

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

What are the different ways of the simulation indicates when an equation is balanced?

yKpoI14uk [10]

When an equation is balanced, the different ways that the simulation indicates are as follows: