Factors of 18: 1; 2; 3; 6; 9; 18
Factors of 27: 1; 3; 9; 27
GCF(18; 27) = 9
<span>18 + 27 = 9 × 2 + 9 × 3 = 9 × (2 + 3) </span>
Answer:
y = 3sin2t/2 - 3cos2t/4t + C/t
Step-by-step explanation:
The differential equation y' + 1/t y = 3 cos(2t) is a first order differential equation in the form y'+p(t)y = q(t) with integrating factor I = e^∫p(t)dt
Comparing the standard form with the given differential equation.
p(t) = 1/t and q(t) = 3cos(2t)
I = e^∫1/tdt
I = e^ln(t)
I = t
The general solution for first a first order DE is expressed as;
y×I = ∫q(t)Idt + C where I is the integrating factor and C is the constant of integration.
yt = ∫t(3cos2t)dt
yt = 3∫t(cos2t)dt ...... 1
Integrating ∫t(cos2t)dt using integration by part.
Let u = t, dv = cos2tdt
du/dt = 1; du = dt
v = ∫(cos2t)dt
v = sin2t/2
∫t(cos2t)dt = t(sin2t/2) + ∫(sin2t)/2dt
= tsin2t/2 - cos2t/4 ..... 2
Substituting equation 2 into 1
yt = 3(tsin2t/2 - cos2t/4) + C
Divide through by t
y = 3sin2t/2 - 3cos2t/4t + C/t
Hence the general solution to the ODE is y = 3sin2t/2 - 3cos2t/4t + C/t
There both types of numbers but a whole number is a number with no exponents or decimals, but decimals are like a broken un half whole number
Answer:
The total number of possibilities are 60.
Step-by-step explanation:
Given:
There are 6 digits and 3,7,9 are odd ones.
To Find:
How many possibilities are there for the rock's age
Solution:
Here condition is that number should start with odd digit
so there 3 number only as odd(3,7,9)
So it leaves 3 repeating numbers i.e.2
So permutation of 5 numbers with 3 odd numbers
So possible arrangement will be
nPr
n=5 ,r=3
So 5P3=5!/3!
And finally for all possibilities as
=3*(5!/3!)
=3*(20)
=60
