y = Acos(Bx) + D;
D = 4, A = 2. Now T = 2π/B = 5π/8, B = 2π/(5π/8) = 16/5
WE get y = 2cos(16/5x) + 4
Answer:
Total 25.45 hours will be taken to empty the pool.
Step-by-step explanation:
Time taken by large pumpkin to empty the pool=40 hours
Time taken by the smaller pumpkins to empty the pool=70 hours
Amount of pool emptied by large pumpkin in one hour=
Amount of pool emptied by small pumpkin in one hour=
Amount of pool emptied in one hour if both pumpkins work together=
+
=
Therefore, the no. of days will be the reciprocal of the amount of work done in one hour ie .
Total 25.45 hours will be taken to empty the pool.
Answer:
0.06
Step-by-step explanation:
3/47
I do y get this but it might be 4