Answer:
Hello There the answer is Δ QUT ≅ Δ SVR. (Proved)
Step-by-step explanation:
See the given diagram below.
Given that QV = SU
⇒ - QV = - SU
⇒ QS - QV = QS - SU
⇒ SV = QU .......... (1)
Now, also given that QT = SR
Then between Δ QUT and Δ SVR,
(i) QT = SR {Given}
(ii) QU = SV {Already prooveed}
and (iii) ∠ QUT = ∠ SVR {They are 90°}
Therefore, by Side-Side-Angle i.e. SSA criteria it is proved that Δ QUT ≅ Δ SVR. (Proved)
Hope it helps!