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2 years ago

If I have a 50.0 liter container that holds 45 moles of gas at a

Chemistry

1 answer:

Darina [25.2K]2 years ago

5 0

V= 50. L n=45 mol T= 200°C = 473k P=?

CP)X 50.L)= (45 mol)(0.0821 light_kimol)(473k)

P = 30am or 4000 kPa

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How many moles would there be in 20.0 g of sodium chloride?

deff fn [24]

Answer:

20.0/1 x 1mole/58.44=0.34

(Atomic mass of salt)

Been a minute since I've done this, but this is how I remember doing it, soo..hope this helps!

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2 years ago

Galvanized nails are iron nails that have been plated with zinc to prevent rusting. The relevant reaction is

umka21 [38]

Answer:

50. 5mol

Explanation:

The mass of Zinc required = 3.30 kg = 3300 grams

The relation between moles and mass is:

$moles=\frac{mass}{atomicmass}$

Atomic mass of Zinc = 65.38g/mol

$molesofZinc=\frac{3300}{65.38}$

$molesofzinc=50.47mol$

The answer to three significant figures will be 50.5 mol

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2 years ago

why was it important to heat your hydrate gently for 5 minutes before heating it strongly for 10 minutes

snow_lady [41]

If the hydrate gets too hot it could start splattering and cause a loss of sample.

6 0

1 year ago

Please help me!!!!!!!!!!!!!

fenix001 [56]

1)The limiting reactant will be aluminum acetate

2) The mass of aluminum hydroxide formed will be 9.75 grams.

<h3>Stoichiometric problem</h3>

The equation of the reaction is as below:

$Al(C_2H_3O_2)_3 + 3NaOH --- > 3C_2H_3NaO_2 + Al(OH)_3$

The mole ratio of the 2 reactants is 1:3.

Mole of 100 mL. 1.25 mol/L $Al(C_2H_3O_2)_3$ = 0.1 x 1.25 = 0.125 mol

Mole of 300 mL, 2.30 mol/L NaOH = 0.3 x 2.3 = 0.69 mol

Thus, aluminum acetate is limited.

Mole ratio of $Al(C_2H_3O_2)_3$ and $Al(OH)_3$ = 1:1

Equivalent mole of $Al(OH)_3$ = 0.125 mol

Mass of 0.125 mole $Al(OH)_3$ = 0.125 x 78 = 9.75 grams.

More on stoichiometric calculations can be found here: brainly.com/question/27287858

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4 0

1 year ago

40 . For the first ionization energy for an N2 molecule, what molecular orbital is the electron removed from

DanielleElmas [232]

Answer:

For the first ionization energy for an N2 molecule, the molecular orbital that the electron is removed from is the p orbital.

It should be noted that valence electrons simply refer to the electrons in an atom that holds the last orbital that is required for chemical bonding with other elements.

The existence of valence electrons can define the chemical properties of that atom. For the first energy in ionization of an N2 molecule, the molecular orbital where the electron could be extracted is the p orbital since it has the highest energy level.

5 0

1 year ago