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2 years ago

What waves disturb matter?

Chemistry

1 answer:

PSYCHO15rus [73]2 years ago

8 0

<span>A mechanical wave is a disturbance in matter that transfers energy through the matter.</span>

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A 6.50x10^-5 m solution of potassium permanganate has a percent transmittance of 27.3% when measured in a 1.15 cm cell at a wave

mihalych1998 [28]

For this problem, we use the Beer Lambert's Law. Its usual equation is:

A = ∈LC
where
A is the absorbance
∈ is the molar absorptivity
L is the path length
C is the concentration of the sample solution

As you notice, we only have to find the absorbance. But since we are not given with the molar absorptivity, we will have to use the modified equation that relates % transmittance to absorbance:

A = 2 - log(%T)
A = 2 - log(27.3)
A = 0.5638

7 0

2 years ago

Radon (Rn) is the heaviest, and only radioactive, member of Group 8A(18) (noble gases). It is a product of the disintegration of

Serggg [28]

Given data Atomic mass of Ra= 226g/mol

no. of moles =1.0/226g/mol =0.04424moles

no. of atoms in 0.044moles

no. of atoms =no. of moles x avogadro's number

= 0.044x 6.022 x10^23 = 0.264968 x 10^22

If 10^15 atoms of Ra produce 1,373*10^4 atoms of<u> Rn per second</u> then 2,66 *10^21 forms 3,658*10^10 atoms of Rn per second.

Day has 246060=86400 s

That means that 2,66x10^21 atoms of Ra produces 3,16 x10^15 atoms of Rn in a day.

N(Rn)=3.16* 10 ^15 n(Rn)=N/NA

n(Rn)=5,25*10−9 pV=nR*T

T=273.15K R=8,314

p=101325Pa V=n∗R∗T/p

V=5.25∗10^−9 ∗ 8.314 ∗ 273.15 / 101325

V=1.1810^−10 m^3 = 118 x10^-7 liters of Rn, measured at STP, are produced per day by 1.0 g of Ra

To know more about Ra here

brainly.com/question/9112754

#SPJ4

6 0

1 year ago

Following the Napoleonic Wars , the congress of vienna took steps meant to:

Slav-nsk [51]

Answer:

Prevent any European country from growing much stronger than its neighbors.

Explanation:

4 0

2 years ago

Can anyone explain how to do this?

Roman55 [17]

Answer:

hello u need help? 9i0

Explanation:

3 0

2 years ago

It takes 412. KJ/mol to break a carbon-hydrogen single bond. Calculate the maximum wavelength of light for which a carbon-hydrog

olga_2 [115]

Answer:

The maximum wavelength of light for which a carbon-hydrogen single bond could be broken by absorbing a single photon = 290 nm

Explanation:

So to break a single C - H bond require = $\frac{412}{6.023 X (10)^{23} }$

= 6.84 x 10⁻¹⁹ joule

Find the wavelength of a photon we use E = hν

⇒ E = $\frac{hc}{Wavelength}$

Where h = Planck's constant = 6.626 x 10⁻³⁴ J.K⁻¹.Mole⁻¹

c = speed of light = 3 x 10⁸ m/sec

Wavelength = $\frac{6.626 X 10^{-34} X 3 X 10^{8} }{6.84 X10^{-19} }$

= 2.9 x 10⁻⁷ m

= 290 nm

∵ 1 nm = 10⁻⁹ m

7 0

3 years ago