Answer:
Explanation:
Hello there!
In this case, according to the given chemical reaction whereas the sodium chloride is in a 2:1 mole ratio with chlorine, the required moles of the later are computed as shown below:
So we cancel out the moles of NaCl to obtain:
Best regards!
Uranium emits particles and rays spontaneously through this process called radioactive decay or radioactivity.
Is the process by which the nucleus of an unstable atom loses energy by emitting radiation, including alpha particles, beta particles. gamma rays and conversion electrons.
Given that,
The concentration of
TRIS = 0.30 M
The concentration of
TRIS+ = 0.60 M
Kb = 1.2 x 10^-6
pKb = -log Kb = - log
(1.2 x 10^-6) = 5.920
Now, by using the
Hendersonn equation,
pH = pKa + log
TRIS+/TRIS = 5.920 + log (0.60/0.30) = 6.221
<span>pOH=14-pH=14-6.221 =
7.779</span>
D = m / V
D = 2790 g / 205 mL
D = 13.60 g/mL
use variable
1K₂MnF₆ + aSbF₅⇒ bKSbF₆ + cMnF₃ + dF₂
K, left=2,right=b⇒b=2
Mn, left=1, right=c⇒c=1
Sb, left=a, right=b⇒a=b=2
F, left=6.1+5a, right=6b+3c+2d
equation:
6+5(2) = 6(2)+3(1)+2d
16=15+2d
1=2d
d=0.5
So the reaction equation becomes:
1K₂MnF₆ + 2SbF₅⇒ 2KSbF₆ + 1MnF₃ + 0.5F₂ x2
2K₂MnF₆ + 4SbF₅⇒ 4KSbF₆ + 2MnF₃ + F₂