What is the slope of the line that passes through the points (5, -11)and (-9, 17)

Mathematics

2 answers:

Lapatulllka [165]2 years ago

4 0

Answer:

The slope of the line is -2

Step-by-step explanation:

Using the slope formula:

$\frac{y_{2}-y_{1}}{x_{2}-x_{1} }$

You can plug in the numbers given in the problem:

$\frac{(17+11)}{(-9-5)}$

$-\frac{28}{14}$

Then simplify to -2

dalvyx [7]2 years ago

3 0

Answer:

Step-by-step explanation:

-2 is the slope for the points listed above.

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bezimeni [28]

Step-by-step explanation:

Remember that in a linear function of the form $f(x)=mx+b$ , $m$ is the slope and $b$ is the why intercept.

Part A. Since $g(x)=2x+6$ , its slope is 2 and its y-intercept is 6

Now, to find the slope of $f(x)$ we are using the slope formula:

$m=\frac{y_2-y_1}{x_2-x_1}$

where

$m$ is the slope

$(x_1,y_1)$ are the coordinates of the first point

$(x_2,y_2)$ are the coordinates of the second point

From the table the first point is (-1, -12) and the second point is (0, -6)

Replacing values:

$m=\frac{y_2-y_1}{x_2-x_1}$

$m=\frac{-6--(12)}{0-(-1)}$

$m=\frac{-6+12}{0+1}$

$m=6$

The slope of f(x) is bigger than the slope of g(x), which means the line represented by f(x) is stepper than the line represented by g(x).

Part B. To find the y-intercept of f(x) we are taking advantage of the fact that the y-intercept of a linear function occurs when x = 0, so we just need to look in the table for the value of f(x) when x = 0. From the table $f(x)=-6$ when $x=0$ ; therefore the y-intercept of $f(x)$ is -6.