Answer:
The ball reaches a height of 29.25 ft after 1.125 seconds
Step-by-step explanation:
The maximum height of a parabola can always be found by looking for the vertex. You can find the x value (or in this case the t value) of a vertex by using -b/2a in which a is the coefficient of x^2 and b is the coefficient of x.
-b/2a
-(36)/2(-16)
-36/-32
1.125 seconds
Now to find the height, we input that value in for t
h = -16t^2 + 36t + 9
h = -16(1.125)^2 + 26(1.125) + 9
29.25 feet
Answer:
Yes
Step-by-step explanation:
Because they are the same equations, just flipped. hope this helped
The average of the given base lengths is the length of the midsegment:
... (72 + 104)/2 = 176/2 = 88
Some things you need to know:
1) You need to know how to convert standard form to slope y-int. form and slope y-int. form to standard form.
2) When two lines are parallel, the slopes are the same.
3) When two lines are perpendicular, the slopes are negative reciprocals of each other. (Or their product is -1)
example: 3/4 --> -4/3.
3/4 * -4/3 = -12/12 = -1
4) To find the value of b, substitute the point into the equation.
5) Convert the equation to slope y-int. form to find the slope.
6) When a line has an undefined slope, the slope y-int. will look either like
y = __ (forms horizontal line) or x = __ (forms vertical line).
To find the perpendicular of these lines, turn y to x / x to y.
To find the value of __, look at the point located in the line, so if x = ___
passes through (5,3), then x = 5 because x = 5 in the point. So the
equation would be x = 5.
Use online practice tests and other sources if you don't understand.
