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2 years ago

5.) The two figures below have the same perimeter. Set up and solve an.

Mathematics

1 answer:

Lunna [17]2 years ago

5 0

Zjdjdjdjdjdfnfjdjdjdj

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HELP PLZZ Which figure shows a reflection of pre-image DEFG over the x-axis?

scoray [572]

The first one is a reflection over the x-axis :)

5 0

2 years ago

What is the relationship between 1 meter and 1 centimeter?

motikmotik

Answer:

there are 100 centimeters in a meter

Step-by-step explanation:

you can remember this by the prefix centi which means 100.

4 0

2 years ago

Write a polynomial function of minimum degree in standard form with real coefficients whose zeros and their multiplicities inclu

Softa [21]

Answer-

The polynomial function is,

$y=x^4-10x^3+38x^2-64x+40$

Solution-

The zeros of the polynomial are 2 and (3+i). Root 2 has multiplicity of 2 and (3+i) has multiplicity of 1

The general form of the equation will be,

$\Rightarrow y=(x-(2))^2(x-(3+i))(x-(3-i))$ ( ∵ (3-i) is the conjugate of (3+i) )

$\Rightarrow y=(x-2)^2(x-3-i)(x-3+i)$

$\Rightarrow y=(x^2-4x+4)((x-3)-i)((x-3)+i)$

$\Rightarrow y=(x^2-4x+4)((x-3)^2-i^2)$

$\Rightarrow y=(x^2-4x+4)((x^2-6x+9)+1)$

$\Rightarrow y=(x^2-4x+4)(x^2-6x+10)$

$\Rightarrow y=x^2x^2-6x^2x+10x^2-4x^2x+4\cdot \:6xx-4\cdot \:10x+4x^2-4\cdot \:6x+4\cdot \:10$

$\Rightarrow y=x^4-10x^3+14x^2+24x^2-40x-24x+40$

$\Rightarrow y=x^4-10x^3+38x^2-64x+40$

Therefore, this is the required polynomial function.

4 0

2 years ago

Graph f(x) =-2x^+16x-30 by factoring to find the solutions, then find the coordinates of the vertex, and the axis of symmetry. I

inn [45]

Answer:

See explanation

Step-by-step explanation:

1. Factor the function $f(x)=-2x^2+16x-30:$

$f(x)=-2x^2+16x-30=-2x^2+6x+10x-30=-2x(x-3)+10(x-3)=-2(x-3)(x-5).$

2. The zeros (or the solutions of the equation f(x)=0) are x=3 and x=5. So? points (3,0) and (5,0) are the points on the graph that are the solutions of the equation.

3. Find the vertex:

$x_v=-\dfrac{b}{2a}=-\dfrac{16}{2\cdot (-2)}=4,\\ \\y_v=-2\cdot 4^2+16\cdot 4-30=-32+64-30=2.$

Thus, the coordinates of the vertex are (4,2) and the axis of symmetry is the vertical line that passes trough the vertex: x=4.

3 0

2 years ago

Which graph best represents the function f(x) = 2x^2 -2

astraxan [27]

Answer:

The u equation, a parabola

Step-by-step explanation:

This is a quadratic equation, since we have a variable 'x' raised to second power.

The vertex can be found using the formula x=-b/2a when the parabola is written as y=ax2 + bx +c.

5 0

2 years ago