Answer:
Density by giving the object it's weight/volume. State of matter by giving its chemical substances and physical shape.
Explanation:
State of matter, (solid, liquid, or a gas) determines the main physical property of a substance. If it's a liquid, it would have an indefinite shape/physical appearance. If the object is a solid than the shape would have a definite shape/physical appearance. Density is defined as mass per volume which means the weight of an object divided by the volume determines the density of the object. You would have the volume (the amount of space an object takes up) and the mass (weight of the object) if you have the objects density.
To conclude, both density and the objects state of matter determine the physical properties of a substance. "Density the weight and volume, and the state of matter is the shape/chemical properties of the substance."
Hope this helps.
(19.78 x 10) + (80.22 x 11) all of them divided by 100= 10.81 amu
Answer:
= 67.79 g
Explanation:
The equation for the reaction is;
4Cr(s)+3O2(g)→2Cr2O3(s)
The mass of O2 is 21.4 g, therefore, we find the number of moles of O2;
moles O2 = 21.4 g / 32 g/mol
=0.669 moles
Using mole ratio, we get the moles of Cr2O3;
moles Cr2O3 = 0.669 x 2/3
=0.446 moles
but molar mass of Cr2O3 is 151.99 g/mol
Hence,
The mass Cr2O3 = 0.446 mol x 151.99 g/mol
<u> = 67.79 g
</u>
Answer:
(C) through the atmosphere
Explanation:
In this item, we are simply to find the ions that may bond and are able to form a formula unit. We are also instructed to give out their name. There are numerous possible combinations of ions to form a compound. Some answers are given in the list below.
1. Na⁺ , Cl⁻ , NaCl ---> sodium chloride (this is most commonly known as table salt)
2. C⁴⁺ , O²⁻ , CO₂ ---> carbon dioxide
3. Al³+ , Cl⁻ , AlCl₃ ----> aluminum chloride
4. Ca²⁺ , Cl⁻ , CaCl₂ ---> calcium chloride
5. Li⁺ , Br⁻ , LiBr ---> lithium bromide
6. Mg³⁺ , O²⁻ , Mg₂O₃ ----> magnesium oxide
7. K⁺ , I⁻ , KI ---> potassium iodide
8. H⁺ , Cl⁻ , HCl --> hydrogen chloride
9. H⁺ , Br⁻ , HBr ----> hydrogen bromide
10. Na⁺ , Br⁻ , NaBr ---> sodium bromide
