The triangles that are similar would be ΔGCB and ΔPEB due to Angle, Angle, Angle similarity theorem.
<h3>How to identify similar triangles?</h3>
From the image attached, we see that we are given the Parallelogram GRPC. Thus;
A. The triangles that are similar would be ΔGCB and ΔPEB due to Angle, Angle, Angle similarity theorem.
B. The proof of the fact that ΔGCB and ΔPEB are similar pairs of triangles is as follow;
∠CGB ≅ ∠PEB (Alternate Interior Angles)
∠BPE ≅ ∠BCG (Alternate Interior Angles)
∠GBC ≅ ∠EBP (Vertical Angles)
C. To find the distance from B to E and from P to E, we will first find PE and then BE by proportion;
225/325 = PE/375
PE = 260 ft
BE/425 = 225/325
BE = 294 ft
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Answer:
1.626 and then theres a lot more numbers
Step-by-step explanation:
We know -48 came from (a)(-6), the "L" in "FOIL".
If -48 = -6a, then a = 8.
Now with a=8, go ahead and FOIL (x+8)(x-6) to find m.
If you dont know. use x as your original value. Therefore. you would have:
x - 15 + 9
after the second stop you would have:
(x - 15 + 9) - 4
So your answer would either be...
There was ______ more people on the bus before 2:30 than there was after the second stop.
There was ______ more people on the bus after the second stop than there was before 2:30.
The cheapest service would be the year in which the mean was the lowest. In Year 4, the mean was the lowest.
The most consistent service would be the year in which the range was the lowest. In Year 3, the range was the lowest.