1. V = lwh
V = (8)(4)(5)
V = (32)(5)
V = 160 units³
2. V = lwh + lwh
V = (4)(2)(1) + (3)(1)(1)
V = (8)(1) + (3)(1)
V = 8 + 3
V = 11 units³
3. V = leh + s³
V = (9)(3)(4) + (3)³
V = (27)(4) + 27
V = 108 + 27
V = 135 units³
4. V = lwh
V = (3)(7)(2)
V = (21)(2)
V = 42 units³
Answer:
take 40 degree as reference angle
using sine rule
let opposite be x
sine 40=opposite/hypotenuse
0.64=x/7
0.64*7=x
4.48=x
Step-by-step explanation:
A measurement that closely agrees with an accepted value is best described as a numerical
To determine the answer of Part A draw the equilateral triangle and the to determine the coordinates of of the third charge use that triangle.
To calculate the gravitational field strength in part B from each of the charges use the following equation.
E=kcq/r2
If you would add those values then you can use the symmetry about the y axis to make the vector addition a litter easier.<span />
<span>Simplify the fractions if not in lowest terms.Multiply the numerators of the fractions to get the new numerator.<span>Multiply the denominators of the fractions to get the new denominator.</span></span>