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2 years ago

When you (survive/accept) you get through something which is it idk

Mathematics

2 answers:

ValentinkaMS [17]2 years ago

8 0

Survive because your persevering through a tough time

Whitepunk [10]2 years ago

7 0

The answer will be survive. Hope it help!

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We want to find the zeros of this polynomial:

SCORPION-xisa [38]

Answer:

x=0 x=2 x=7/2

Step-by-step explanation:

P(x) = 3x (x - 2) (2x - 7)

Set equal to zero

0 = 3x (x - 2) (2x - 7)

Using the zero product property

3x =0 x-2 =0 2x-7 =0

x=0 x=2 2x=7

x=0 x=2 x=7/2

6 0

2 years ago

James earned $334 4 working a 40-hour week how much will he earn in a week in which he works only 32 hours

monitta

$267.20 all I did was cross multiply

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2 years ago

Solve the equation. −t/4=−3π

devlian [24]

−t4=(−3)(3.141593)Step 1: Simplify both sides of the equation.−14t=−9.424778Step 2: Multiply both sides by 4/(-1).(4−1)*(−14t)=(4−1)*(−9.424778)t=37.699112

8 0

2 years ago

Read 2 more answers

Mathematical induction of 3k-1 ≥ 4k ( 3k = k power of 3 )

tresset_1 [31]

For making mathematical induction, we need:

a base case

An $n_0$ for which the relation holds true

the induction step

if its true for $n_i$ , then, is true for $n_{i+1}$

the relationship is not true for 1 or 2

$1^3-1 = 0 < 4*1$

$2^3-1 = 8 -1 = 7 < 4*2 = 8$

but, is true for 3

$3^3-1 = 27 -1 = 26 > 4*3 = 12$

<h3>induction step</h3>

lets say that the relationship is true for n, this is

$n^3 -1 \ge 4 n$

lets add 4 on each side, this is

$n^3 -1 + 4 \ge 4 n + 4$

$n^3 + 3 \ge 4 (n + 1)$

now

$(n+1)^3 = n^3 +3 n^2 + 3 n + 1$

$(n+1)^3 \ge n^3 + 3 n$

if $n \ge 1$ then $3 n \ge 3$ , so

$(n+1)^3 \ge n^3 + 3 n \ge n^3 + 3$

$(n+1)^3 \ge n^3 + 3 \ge 4 (n + 1)$

$(n+1)^3 \ge 4 (n + 1)$

and this is what we were looking for!

So, for any natural equal or greater than 3, the relationship is true.

4 0

2 years ago

Graph f(x)=2^x+1 and g(x)=-x+4 on the same coordinate plane what is the solution to the equation f(x)=g(x)

Leona [35]

Answer:

x = 1

Step-by-step explanation:

The graph shows the curves cross at x=1.

The solution is x = 1.

Additional comment

I personally find it more convenient to look for the zeros (x-intercepts) of the difference f(x)-g(x). That way, I'm only graphing one function, and I don't have to look all over the graph to try to find the point of intersection. (The solution is always on the x-axis.) The attached graph shows f(x) - g(x) as a dashed green line.

3 0

1 year ago