There are 10 balls in the Urn Total.
Red: 6
Green: 4
Question One: The probability that five red and two green is selected is likely. (as that is over half for both)
Question Two: Impossible. There is only 6 red balls, and 7 are taken from the urn. Thus it would at most be possible for 6 red and 1 green.
Question Three: At least four is likely, as there is more red then green in the Urn.
Hope I helped!
(Mark Brainliest if you can please!)
Answer:
(4x² + 24x + 35) in²
Step-by-step explanation:
(5+2x)(7+2x)
35 + 14x + 10x + 4x²
4x² + 24x + 35
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