Answer:
The base (b) has to be positive and different of 1. The logarithm is the inverse of exponential, so:
logb(a) = x ⇒ a = bˣ
So, for b = 0 ⇒ 0ˣ = a
And there is impossible, "a" only could be 0.
For b = 1 ⇒ 1ˣ = a
And the same thing would happen, the logarithming would be to be 1, and the function will be extremally restricted.
For b<0, then the expression a = bˣ will be also restricted, and will not represent all values of a.
So, 0<b<1 and b >1.
Answer:C.40
Step-by-step explanation:
In the case of exponential functions, the graph is shifted when a constant is added to the exponent of the constant. The original equation, f(x) is:
f(x) = (1/2)ˣ
Now, when horizontal shifting is occurring, the equation is:
y = Cˣ⁺ᵃ
If a is positive, the graph shifts to the lefts and the shift is equal to a units. If a is negative, the graph shifts to the right and the shift is equal to a units. Therefore, to shift the graph 3 units to the left:
g(x) = (1/2)⁽ˣ⁺³⁾
The correct answer is B.
Y=2x+3
for x = -3 y = 2*(-3)+3=-6+3=-3
for x = -1 y = 2*(-1)+3=-2+3=1
for x = 2 y = 2*2+3 = 4+3 = 7
for x = 4 y = 2*4+3 = 8+3 =11
for x = 5 y = 2*5+3 = 10+3 =13