Both of you are overlooking a pretty big component of the question...the Group I cation isn't being dissociated into water. We're testing the solubility of the cation when mixed with HCl. And this IS a legitimate question, seeing as our lab manual is the one asking.
<span>By the way, the answer you're looking for is "Because Group I cations have insoluble chlorides". </span>
<span>"In order...to distinguish cation Group I, one adds HCl to a sample. If a Group I cation is present in the sample, a precipitate will form." </span>
Answer:
Ether
SN1 mechanism
Explanation:
The nucleophile in this reaction is CH3OH. It is a poor nucleopile. We already know that a poor nucleophile reacting with a tertiary alkyl halide often leads to the substitution product as the major product.
Also, the iodide ion is a good leaving group. This makes the SN1 substitution more likely yielding the ether as the major product as shown in the image attached.
Answer:
1. NaOH + H₂O → Na⁺ + OH⁻ + H₂O + heat
2. NaOH + HCl → NaCl + H₂O
Explanation:
1. The dissolving of NaOH in water is an exothermic reaction resulting a heat. It also causes the dissociation of NaOH to its ions (Na⁺ and OH⁻).
So, the balanced equation will be NaOH + H₂O → Na⁺ + OH⁻ + H₂O + heat.
2. The reaction between acid and base resulting salt and water. It is considered as a neutralization reaction.
The reaction between HCl and NaOH will give sodium chloride and water and the balanced equation will be NaOH + HCl → NaCl + H₂O.
