Answer:
<em> (a). ∠UXV, ∠XVY ; (b). UV = 8 m .</em>
Step-by-step explanation:
<span>The factors of 60 are 60, 30, 20, 15, 12, 10, 6, 5, 4, 3, 2, 1.The factors of 75 are 75, 25, 15, 5, 3, 1.<span>The common factors of 60 and 75 are 15, 5, 3, 1, intersecting the two sets above.</span><span>In the intersection factors of 60 ∩ factors of 75 the greatest element is 15.</span><span>Therefore, the greatest common factor of 60 and 75 is 15.
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Answer:
Step-by-step explanation:
6< 3x + 9
-3x < 9-6
-3x < 3 .( -1 )
3x > 3
x > 3/3
x > 3
3x + 9 ≤ 18
3x ≤ 18-9
3x ≤ 9
x ≤ 9/3
x ≤ 3
S = {XeIR/ 3 > x ≤ 3 }
Not sure if the solution looks like this
The probability that he selected the special quarter is 87.5%.
<h3><u /></h3><h3><u>Probability</u></h3>
Given that Mandvil has one standard quarter and one special quarter with a Head on both sides, and he selects one of these two coins at random, and without looking at it first, he flips the coin three times, to determine, if he flips a Head three straight times, what is the probability that he selected the special quarter, the following calculation must be made:
- 1 - (standard quarter) = X
- 1 - (0.50^3) = X
- 1 - 0.125 = X
- 0.875 = X
- 0.875 x 100 = 87.5
Therefore, the probability that he selected the special quarter is 87.5%.
Learn more about probability in brainly.com/question/24217562
The answer is 69.08 in || to get this you use the formula c=(pi)d and you plug in your numbers c=(3.14)(22)