Answer: Within each element square, information on the element's symbol, atomic number, atomic mass, electronegativity, electron configuration, and valence numbers can be found. At the bottom of the periodic table is a two row block of elements that contain the lanthanoids and actinides.
For plato users
the answer is a. O2(l) O2(g)
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Answer:
V = 81.14 L
Explanation:
Given data:
Volume of gas = ?
Number of moles = 3.30 mol
Temperature of gas = 25°C
Pressure of gas = 0.995 atm
Solution:
The given problem will be solve by using general gas equation,
PV = nRT
P= Pressure
V = volume
n = number of moles
R = general gas constant = 0.0821 atm.L/ mol.K
T = temperature in kelvin
Now we will convert the temperature.
25+273 = 298 K
now we will put the values in formula:
V = 3.30 mol 0.0821 atm.L/ mol.K 298 K / 0.995 atm
V = 80.74 L. atm / 0.995 atm
V = 81.14 L
Answer : The mass of sulfuric acid needed is .
Solution : Given,
pH = 8.94
Volume of solution = 380 ml =
Molar mass of sulfuric acid = 98.079 g/mole
As we know,
Now we have to calculate the moles of .
Formula used :
For neutralization, equal number of moles of ions will neutralize same number of ions.
As,
From this reaction, we conclude that
2 moles of ion is given by the 1 mole of
moles of ion is given by moles of
Now we have to calculate the mass of sulfuric acid.
Mass of sulfuric acid = Moles of × Molar mass of sulfuric acid
Mass of sulfuric acid =
Therefore, the mass of sulfuric acid needed is .
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