Answer:
-1<x<9
(I think you notated it wrong, it should be |x-4|-2<3)
Your answer is B.
Flat fee is $250, so we cannot change this number.
585 - 250 = 335
335 (remaining cash) divided by 8 (price per student) = 41.875
Since we can't bring .8 of one student on the trip, we will round the number down to 41, because if we round up we will go over the budget of $585.
The maximum number of students a school can send is 41.
Answer:
Step-by-step explanation:
Since these are like-terms, they can be added together.
7z + 7z = 14z
Answer:
B
Step-by-step explanation:
Using the determinant to determine the type of zeros
Given
f(x) = ax² + bx + c ( a ≠ 0 ) ← in standard form, then the discriminant is
Δ = b² - 4ac
• If b² - 4ac > 0 then 2 real and distinct zeros
• If b² - 4ac = 0 then 2 real and equal zeros
• If b² - 4ac < 0 then 2 complex zeros
Given
f(x) = (x - 1)² + 1 ← expand factor and simplify
= x² - 2x + 1 + 1
= x² - 2x + 2 ← in standard form
with a = 1, b = - 2, c = 2, then
b² - 4ac = (- 2)² - (4 × 1 × 2) = 4 - 8 = - 4
Since b² - 4ac < 0 then the zeros are complex
Thus P(x) has no real zeros
Answer:
Let x equal the ice thickness. An equality that represents a safe ice thickness for walkability is:
x ≥ 4 inches
(Plus the graph)
Step-by-step explanation:
Defining a variable just means you let any letter or symbol take the place of something. But you have to specifically say what is what in order for it to be clear.
So I defined "x" as the variable to represent the ice's thickness. And since we want an inequality for all the safe thicknesses, we could say that "x" must be greater than or equal to 4 inches thick in order to safely walk on it.
Lastly, you'd graph it with a solid point on 4 with the arrow going to the right.