Answer:
The zeros of f(x) are: (x - 1), (x - 3) and (x - 8)
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Step-by-step explanation:
Given
Required
Find all zeros of the f(x)
If then:
And 
is a factor
Divide f(x) by x - 8
Expand the numerator
Rewrite as:
Factorize
Expand
Factorize
Multiply both sides by x - 8
<em>Hence, the zeros of f(x) are: (x - 1), (x - 3) and (x - 8)</em>
• Expand (2a + b)²:
(2a + b)²
= (2a + b) · (2a + b)
Multiply out the brackets by applying the distributive property of multiplication:
= (2a + b) · 2a + (2a + b) · b
= 2a · 2a + b · 2a + 2a · b + b · b
= 2²a² + 2ab + 2ab + b²
Now, group like terms together, and you get
= 2²a² + 4ab + b²
= 4a² + 4ab + b² <——— expanded form (this is the answer).
I hope this helps. =)
Tags: <em>special product square of a sum algebra</em>
The difference between each number in the dollars fund is 25
209 - 184 = 25
184 - 159 = 25
so....in the ? space......134 - 25 = 109 <==
Answer:
36
Step-by-step explanation:
The number in the first column is multiplied by 6 to get the number in the second column. 6 times 6 = 36.
I'm extremely sorry if it's wrong.
