Answer:
The test was not statistically significant because if the null hypothesis is true, one could expect to get a test statistic at least as extreme as that observed 21% of the time.
Step-by-step explanation:
This is the right answer,since this result is only observed 21% of the time, so in general it's not significant, so the first 2 are eliminated. The 2 x 0.21 doesn't matter since, the percent is 21% not 42%, so it doesn't even matter. The last question we eliminate is:"The test was not statistically significant because if the null hypothesis is true, one could expect to get a test statistic at least as extreme as that observed 79% of the time" 79% of the time is a pretty good amount to say it's significant, but it only says 21% of the time.So, it leaves us with:The test was not statistically significant because if the null hypothesis is true, one could expect to get a test statistic at least as extreme as that observed 21% of the time.
Hope this helps lol (: is this a psat or somethin?
To best estimate the volume of the log, we assume that the diameter is the average of the diameters at both ends giving us 12 inches as the diameter. Thus, the radius is equal to 0.5 ft. The volume of the log is calculated through the equation,
V = πr²h = π(0.5 ft)²(10 ft) = 7.85 ft³
The second one is the correct answer