Answer:
11. b
10.d
9.c
7.b
1.d
the rest I can't see clearly
please give brainiest
Step-by-step explanation:
11.
3/x-4=7/x
*cross multiply
3x=7 (x-4)
3x=7x-28
28=7x-3x
28=4x
x=7
10.
SOHCAHTOA
Cos☆=11/14
cos^-1 (11/14)
☆=38.21 degrees
9.
MLN CONGRUENT TO WBN
ML/WB=LN/BN=MN/WN
LN/BN=10/6
ML/WB
24/x=10/6
24x6=10x
144÷10
=14.4
6^2+14.4^2
=243.36
squareroot
=15.6
200/160=1.25
200+160=360/1.25/160=200.8
so your answer is 0.8
These problems are called systems of equations. Basically you have two linear equations and you need to find the values for x and y. In other words, all these equation are lines and our answer will be the exact point that the pair of lines intersect. For example, if we get x=1 and y=2 the lines will intersect at point (1,2). Now that you have some background knowledge here comes the tricks and tactics kid.
We know that we can solve one variable equation easily. For example...
x+1=2
x=1 obviously
Cause we have two variables x and y it is not possible to find a solution. For example, in the equation x+y=10, x=1 when y=9 and x=2 when y=8. There is not correct answer.
So what can we do? We have to make a two variable equation into a one variable equation.
There are two ways to do this: substitution and elimination. I will create a sample problem and then solve it using both methods.
x+y=2
2y-y=1
3)
-3x-5y=-7 -----> -12x-20y=-28
-4x-3y=-2 ------> -12x-9y=-6
-12x-20y=-28
-(-12x-9y=-6)
---------------------
-11y=-22
y=2
-3x-5(2)=-7
-3x=3
x=-1
4) 8x+4y=12 ---> 24x+12y=36
7x+3y=10 ---> 28x+12y=40
28x+12y=40
-(24x+12y=36)
---------------------
4x=4
x=1
8(1)+4y=12
4y=4
y=1
5) 4x+3y=-7
-2x-5y=7 ----> -4x-10y=14
4x+3y=-7
+(-4x-10y=14)
-------------------
-7y=7
y=-1
4x+3(-1)=-7
4x=-4
x=-1
6) 8x-3y=-9 ---> 32x-12y=-36
5x+4y=12 ---> 15x+12y=36
32x-12y=-36
+(15x+12y=36)
--------------------
47x=0
x=0
8(0)-3y=-9
-3y=-9
y=3
7)-3x+5y=-2
2x-2y=1 ---> x-y=1/2 ----> x=y+1/2
-3(y+1/2)+5y=-2
-3y-1.5+5y=-2
2y=-0.5
y=0.25
2x-2(0.25)=1
2x=1.5
x=0.75
Answer: 
Step-by-step explanation:
1. You have the following formula for calculate the area of the original circular chip:
Where D is the diameter of the circle.
2. Then, if the diameter of the original circular chip is doubled (2D) to use in a new board game, the area of the new chip can be calculated with the following formula:
