Answer:
Step-by-step explanation:
we have to find formula for nth term of series for this problem
Thus, we see series is 12, 9 ,6
Thus, we can see that series is decreasing by unit of 3.
and we know that when there is in increase or decrease in series by a a constant number then series is arithmetic progression series.
Hence, this is a decreasing AP series
In AP
nth term is given
nth term = a+(n-1)d
where a is the first term
d is the common difference
common difference is given by = nth term - (n-)th term
lets take 2nd and 1st term to get common difference.
d = 9-12 = -3
(note: this was obvious by looking at series itself that d is -3 as series was decreasing by 3 unit)
a = 12
thus, nth term = a +(n-1)d
nth term = 12 +(n-1)(-3)
nth term = 12 -3(n-1)
writing this in form of
Answer
In the month of <u>October</u>, the <u>population</u> of a species of fish in a river <u>increased</u> by a factor of 1.05 every day. The function below shows the number of fish in the river f(x) after x days:
The reasonable domain of the function will be the number of days of the period when the population is explored. The research take place in October, this month has 31 days, thus, the reasonable domain is
0 ≤ x ≤ 31
Answer: 0 ≤ x ≤ 31
Applying the translation rule, the coordinates are:
- A'(-1,12).
- B'(3, -3).
- C'(-15, 22).
The translation rule is:
Thus, for the image, the transformation is applied for each coordinate. Then:
A similar problem is given at brainly.com/question/24721131
<span><span>(x - h)^2 + (y - k)^2 = r^2
</span><span>(x - (-3/5))^<span>2 </span>+ (y - (-4/5))^2 = (1)^2
(x + 3/5)^2 + (y + 4/5)^2 = 1
answer is D.
</span></span>(x + 3/5)^2 + (y + 4/5)^2 = 1