Answer:
Maximum = 756
Minimum = 600
Step-by-step explanation:
A square is a shape that has the large areas of a defined perimeter out of available rectangles. It implies they want the two parentheses to be as similar in value. as a result, to establish the maximum value of P.
And to establish the minimum value, to have the greatest difference for them. 1 + 2 + 3 ... +10=55, which wasn't even but which can be split as similarly as possible into 27 and 28 which have a product of 756. In this question it can be done in a variety of ways, one of which is:
(1 + 3 + 5 + 8 + 10) × (2 + 4 + 6 + 7 + 9) = 756
At the very least, the biggest difference can be created if one term is made of the smallest numbers, while the other full of the highest, or:
(1 + 2 + 3 + 4 + 5) × (6 + 7 + 8 + 9 + 10)=600
Answer:
24.27 cm
Step-by-step explanation:
sin 65 degrees = 22/x, so:
1 x
------------------ = ------
sin 65 deg 22
so x = 22 / (sin 65 deg) = 22/0.906 = 24.27 cm
You forgot to post the function
Ok, so remember that the derivitive of the position function is the velocty function and the derivitive of the velocity function is the accceleration function
x(t) is the positon function
so just take the derivitive of 3t/π +cos(t) twice
first derivitive is 3/π-sin(t)
2nd derivitive is -cos(t)
a(t)=-cos(t)
on the interval [π/2,5π/2) where does -cos(t)=1? or where does cos(t)=-1?
at t=π
so now plug that in for t in the position function to find the position at time t=π
x(π)=3(π)/π+cos(π)
x(π)=3-1
x(π)=2
so the position is 2
ok, that graph is the first derivitive of f(x)
the function f(x) is increaseing when the slope is positive
it is concave up when the 2nd derivitive of f(x) is positive
we are given f'(x), the derivitive of f(x)
we want to find where it is increasing AND where it is concave down
it is increasing when the derivitive is positive, so just find where the graph is positive (that's about from -2 to 4)
it is concave down when the second derivitive (aka derivitive of the first derivitive aka slope of the first derivitive) is negative
where is the slope negative?
from about x=0 to x=2
and that's in our range of being increasing
so the interval is (0,2)
