Check the picture below. So, more or less looks like so.
notice, the center is clearly at the origin, and notice how long the "a" component is, also, bear in mind that, is opening towards the y-axis, that means the fraction with the "y" variable is the positive one.
Also notice, the "c" distance from the center to either foci, is just 5 units.
Answer:
2.98
Step-by-step explanation:
<span>If
Ellen deposited 6 773 dollars in her account and did not withdraw any amount
for 7 years.
Then she will earn this amount.
=> 1% interest rate per year
=> first year = 6 773 x .01 = 67.73
=> 6773 + 67.73 = 6840.73
=> Second year = 6840.76 * .01 = 68.4073
=> 68.4073 + 6840.76 = 6909.1673
=> Third year = 6909.1673 * .01 = 69.09
=> 6909.1673 + 69.09 = 6978.26
=>4th year = 6978.26 * .01 = 69.78
=> 6978.26 + 69.78 = 7004
=> 5th year = 7004 *.01 = 70.04
=> 7004 + 70.04 = 7074.04
=> 6th year = 7074.04 * .01 = 70.74
=> 70.74 + 7074.04 = 7144.78
=> 7th year = 7144.78 *.01 = 74.45
=> 7144.78 + 74.45 = 7216.23</span>
Answer:
7
Step-by-step explanation:
35 / 7 = 5
49 /7 = 7
Answer:
$95.78
Step-by-step explanation:
f(t) = 300t / (2t² + 8)
t = 0 corresponds to the beginning of August. t = 1 corresponds to the end of August. t = 2 corresponds to the end of September. So on and so forth. So the second semester is from t = 5 to t = 10.
$T₂ = ∫₅¹⁰ 300t / (2t² + 8) dt
$T₂ = ∫₅¹⁰ 150t / (t² + 4) dt
$T₂ = 75 ∫₅¹⁰ 2t / (t² + 4) dt
$T₂ = 75 ln(t² + 4) |₅¹⁰
$T₂ = 75 ln(104) − 75 ln(29)
$T₂ ≈ 95.78