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2 years ago

How do you get the average of something

Mathematics

2 answers:

Irina-Kira [14]2 years ago

7 0

Answer:

add all the numbers together then divide that number my all the numbers you have

Step-by-step explanation: lets say you have 10,20,43,52,65 if you add them together you would get 190 so you would divide by the amount of numbers you have which would be 5 and the average for that set is 38

kogti [31]2 years ago

6 0

The mean is the average of the numbers. It is easy to calculate: add up all the numbers, then divide by how many numbers there are. In other words it is the sum divided by the count.

You might be interested in

What percent of 7 is 2?

Liono4ka [1.6K]

It is 350% I think, because you are trying to find how many groups of 2 go into 7. So, you have to divide 7 by 2. You get 3.5. 3.5 in percentage form is 350%

6 0

2 years ago

One gram of water has a volume of 1 millimeter. What is the volume of the water if it has a mass of 1 kilogram

Zinaida [17]

There are 1,000 grams in a kilogram.
Each gram of water has a volume of 1 milliliter (the question said millimeter but that measures length and I think it was meant to say milliliter).
Since there are 1,000 grams with a volume of 1 millimeter each, the volume is 1,000 milliliters, which is equal to 1 liter.
Hope this helps!

8 0

2 years ago

Consider the following pair of points.

dedylja [7]

Answer:

The answer is

<h2> $\sqrt{265} \: \: or \: \: 16.28 \: \: \: \: units$ </h2>

Step-by-step explanation:

The distance between two points can be found by using the formula

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

(9,-8) and (-7,-5)

The distance between them is

$d = \sqrt{ ({9 + 7})^{2} + ({ - 8 + 5})^{2} } \\ = \sqrt{ {16}^{2} + ( { - 3})^{2} } \\ = \sqrt{256 + 9} \: \: \: \: \: \: \: \: \: \\ = \sqrt{265} \: \: \: \: \: \: \\ = 16.27882$

We have the final answer as

$\sqrt{265} \: \: or \: \: 16.28 \: \: \: \: units$

Hope this helps you

4 0

2 years ago

The answer to these please!

igomit [66]

$\sqrt[4]{(4a^{2})^{6}} = \sqrt[4]{4096a^{12}} = 8a^{3}$

$\sqrt[7]{(b^{\frac{5}{3}})^{8}} = \sqrt[7]{b^\frac{40}{3}} = b^{\frac{40}{21}} = \sqrt[21]{b^{40}} = \sqrt[21]{b^{21} * b^{19}} = \sqrt[21]{b^{21}} \sqrt[21]{b^{19}} = b\sqrt[21]{b^{19}}$

$\sqrt[3]{\frac{c^{9}}{c^{3}}} = \sqrt[3]{c^{6}} = c^{2}$

$\sqrt[3]{27d^{6} * 8d^{-4}} = \sqrt[3]{27d^{6} * \frac{8}{d^{4}}} = \sqrt[3]{216d^{2}} = 6\sqrt[3]{d^{2}} = 6d^{\frac{2}{3}}$

4 0

2 years ago

Read 2 more answers

Can someone expert help me in this please?

Inessa [10]

Does the person have to be expert? Because I can help?

5 0

2 years ago