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2 years ago

Which is an example of a plasma that occurs in nature?

2 answers:

5 0

"B. The radiant sun.
The Sun, like all stars, is a huge plasma ball of very high density and temperature. It consists almost entirely of hydrogen, with a small component of helium and all other elements in smaller proportions.
Although the plasma in the deep interior of the Sun has a chaotic movement, towards its surface and on it the movements of the plasma are already more ordered. Below the surface of the Sun the plasma circulates up and down, forming cells called convection, and on the surface and already in its atmosphere the movements of the plasma are strongly controlled by local magnetic fields of varying intensity and varied structure."

Roman55 [17]2 years ago

4 0

Answer: Option (b) is the correct answer.

Explanation:

Plasma is defined as a state of matter which is a hot ionized gas with positively charged ions and negatively charged electrons.

For example, the hydrogen and helium atoms present inside the Sun exist in plasma state.

This is because inside the Sun nuclear reactions take place due to which the gases are present in hot ionized form and they travel rapidly from one place to another.

Thus, we can conclude that radiant Sun is an example of a plasma that occurs in nature.

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If a gas occupies 1532.7 mL at standard temperature, what volume does it occupy at 49.4 ºC if the pressure remains constant?

ElenaW [278]

Answer:

a. 1810mL

Explanation:

When conditions for a gas change under constant pressure (and the number of molecules doesn't change), it follows Charles' Law:

$\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}$ where the temperatures must be measured in Kelvin

To convert from Celsius to Kelvin, add 273, or use the equation: $T_C+273=T_K$

For this problem, one must also recall that standard temperature is 0°C (or 273K).

So, $T_1 = 273[K]$ , and $T_2 = (49.4+273)[K]=322.4[K]$ .

$\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}$

$\dfrac{(1532.7[mL])}{(273[K])}=\dfrac{V_2}{(322.4[K])}$

$\dfrac{(1532.7[mL])}{(273[K\!\!\!\!\!{-}])}(322.4[K\!\!\!\!\!{-}] )=\dfrac{V_2}{(322.4[K]\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{----})}(322.4[K]\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{----})$

$1810.04571428[mL]=V_2$

Adjusting for significant figures, this gives $V_2=1810[mL]$

4 0

1 year ago

Which of the following is considered a STRONG electrolyte? C12H22O11 HC2H3O2 PbCl2 CH3OH NH4NO3? please explain

PIT_PIT [208]

I believe the correct answer from the choices listed above is the fifth option. Of the following , the strong electrolyte would be NH4NO3. NH4NO3<span> is a salt and completely dissociates in aqueous solution. Hope this answers the question. Have a nice day.</span>

6 0

2 years ago

Does the chemical symbol of the element beryllium correspond to the name of the element?

LenKa [72]

Yes it does, its derived from the greek name for beryl, or beryllo

5 0

2 years ago

Iron-59 has a half-life of 45.1 days. how old is an iron nail if the fe-59 content is 25% that of a new sample of iron? show all

Yuliya22 [10]

I have attached a paper with the answer. hope you understand. let me know if you have any question

4 0

3 years ago

Read 2 more answers

6.0 moles of Na and 4.0 moles of Cl2 are mixed, how manu moles of NaCl in moles cane be made from this mixture

Sladkaya [172]

Answer:

Moles of NaCl formed is 6.0 moles

Explanation:

We are given the equation;

2 Na(s) + Cl₂(g) → 2 NaCl(s)

Moles of Na is 6.0 moles
Moles of Cl₂ is 4.0 moles

From the reaction;

2 moles of sodium reacts with 1 mole of chlorine gas to form 2 moles of NaCl

In this case;

6 moles of Na would require 3 moles of Cl₂, this means that chlorine gas is in excess.

Thus, the rate limiting reagent is sodium.

But, 2 moles of sodium reacts to form 2 moles of NaCl

Therefore;

Moles of NaCl = Moles of Na

= 6.0 moles

Thus, moles of sodium chloride produced is 6.0 moles

3 0

2 years ago