Given the geometric progression below
The nth term of a geometric progression is given below
From the geometric progression, we can deduce the following
To find the value of r, we will take ratios of two consecutive terms
To find the 9th term of the geometric, we will have that;
Hence, the 9th term of the geometric progression is 1953125
You can reword the equation 6x+y=9 to
Y=6x+9
Then plug-in y=6x+9 into the equation 2x+3y=-5
Plug this 2x+3(6x+9)=-5
2x+18x+27=-5
Then solve it from there
Happy New Year from MrBillDoesMath!
Answer:
1, -2, -3
Discussion:
The real roots of the polynomials are factors of the last term (6) divided by the first term (1). The factors of 6/1 or 6 are 1,2,3, and 6. I found by substitution that x= 1 was a solution, divided the polynomial by x-1, came up with a quadratic (x^2 + 5x + 6), and found the remaining roots via the quadratic formula.
Thank you,
MrB
Answer:
hello
Step-by-step explanation:
ok so he had 120 brinjal plants 90 ladys finger plant 45 chilli plants
ok so a storm came along
120/12
90/3
45/29
i think its right if not im so sorrry
