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2 years ago

I need help!! 23=x-9;x=14

Mathematics

1 answer:

soldier1979 [14.2K]2 years ago

7 0

I'm not quite understanding what your question is.

If 23 = x - 9 , then x = 32 , not 14.

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Find the interquartile range of the data.

likoan [24]

The answer is 14. Here is how I work it out.

First we are going have to identify quartile 1 and quartile 3.

So after putting the numbers in order from least to greatest mark the number with a half way point.

This is optional but it will help us spot the sections better.

31,33,35,41,43,|46,48,49,49,50

Next put parentheses around the remaining groups of numbers.

(31,33,35,41,43,)|(46,48,49,49,50)

For the next step we have to find the median of each group.

(31,33,35,41,43,)|(46,48,49,49,50)

The median of each group, are called the quartiles, the median of the lower half is quartile 1, and the median of the upper half is quartile 3.

Now subtract quartile 1 from quartile 3.

49 – 35 = 14

So the interquartile range of this data set is 14.

4 0

2 years ago

Find the average rate of change for f(x) = x2 + 9x + 18 from x = −10 to x = 10.

igor_vitrenko [27]

The average rate of change formula is
f(b) - f(a)
arc = ----------------
b-a

Here, a= -10 and b = 10

(10)^2 + 9(10) + 18 - [ (-10)^2 + 9(-10) + 18]
Here arc = --------------------------------------------------------------
10 - (-10)

10^2 and -(-10)^2 cancel. 18 - 18 cancel.

90 - (-90) 180
This leaves us with arc = ----------------- = ------------- = 9 (answer)
20 20

7 0

2 years ago

A rectangle or piece of paper has a width is 3 inches less than its link it is cut in half along a diagonal to create two congru

kolezko [41]

The length and width of the rectangle is 11 in and 8 in respectively.

Step-by-step explanation:

Given,

The width of a rectangle is 3 in less than the length.

The area of each congruent right angle triangle = 44 in²

To find the length and width of the rectangle.

Formula

The area of a triangle with b base and h as height = $\frac{1}{2}$ bh

Now,

Let, the width = x and the length = x+3.

Here, for the triangle, width will be its base and length will be its height.

According to the problem,

$\frac{1}{2}$ ×(x+3)×x = 44

or, $x^{2} +3x = 88$

or, $x^{2} +3x-88 = 0$

or, $x^{2}$ +(11-8)x-88 = 0

or, $x^{2}$ +11x-8x-88 =0

or, x(x+11)-8(x+11) = 0

or, (x+11)(x-8) = 0

So, x = 8 ( x≠-11, the length or width could no be negative)

Hence,

Width = 8 in and length = 8+3 = 11 in

3 0

2 years ago

Please help with this

marta [7]

9514 1404 393

Answer:

see attached

Step-by-step explanation:

13. The difference of two matrices is the term-by-term difference. For example, the bottom right term is the difference of the bottom right terms ...

(-6) -(5) = -11

14. The scalar multiple of a matrix is the scalar multiplied by each term of the matrix. For example, the upper right term is ...

3(1) = 3

15. The matrix product is the dot product of the rows of the left matrix with the columns of the right matrix. For example, the product term in row two, column one is the dot product of row 2 of C and column 1 of B:

[9, -2, 4]·[-2, -7, 10] = 9(-2) +(-2)(-7) +4(10) = -18 +14 +40 = 36

_____

It is convenient to let an appropriate tool help with this. Many graphing calculators and spreadsheets are able to do these functions easily.

7 0

1 year ago

Some please help I need assistance

ololo11 [35]

Okay it’s the second one

7 0

2 years ago