Here's one way:
A=WxL
So in this case, it's 2x5
You would draw the rectangle, label one side 2 in. and the other 5 in. Draw an arrow from each no./side and put x underneath the line so that its 2 —x— 5 (2, line, x, line, 5. With x under line)
(x,y) = (r,16)
With this knowledge, plug in r for x, and 16 for y
16 = 2(r) - 4
Isolate the r, add 4 to both sides
16 (+4) = 2r - 4 (+4)
20 = 2r
Divide 2 from both sides
20/2 = 2r/2
r = 20/2
r = 10
hope this helps
Answer:
(10^11)/3
10^6 x 10^5 = 10^11
8/5 x 5/24 = 1/3
so multiply 10^11 and 1/3 together
Answer:
The solution to the system of equations (x, y) = (2, 4) represents the month in which exports and imports were equal. Both were 4 in February.
Step-by-step explanation:
We're not sure what "system of equations" is being referenced here, since no equations are shown or described.
__
Perhaps your "system of equations" is ...
f(x) = some equation
g(x) = some other equation
Then the solution to this system of equation is the pair of values (x, y) that gives ...
y = f(x) = g(x)
If x represents the month number, then the solution can be read from the table:
(x, y) = (2, 4)
This is the month in which exports and imports were equal. Both numbers were 4 in February.
400/160=2.5 This is finding the necessary multiplier
2.5*5=x I used 2.5 and multiplied it by 5
x=12.5 minutes This is the answer
It would take 12 minutes and 30 seconds