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2 years ago

Find the mean,median,and mode for the data.

Mathematics

2 answers:

DochEvi [55]2 years ago

4 0

Mean: 116

Median: 115

Mode : 114

Hope this helps!

svet-max [94.6K]2 years ago

4 0

Answer:

Mean: 116

Median: 115

Mode: 115

Step-by-step explanation:

Mean is the average of the data set; it’s found by adding up all the numbers and dividing that sum by the number of numbers there are

(114 + 120 + 115 + 114 + 118 + 117 + 114)/7 = 812/7 = 116

Median is found out by ordering the given numbers from largest to smallest and finding the middle number; if there are an even number of given numbers, you add them up and divide by two.

In this case, you are lucky enough to be given an odd numbers of given numbers

Ordering (smallest to largest):

114, 114, 114, 115, 117, 118, 120

Median is 115

(this is the number in the middle of the data set)

Mode is the most frequently occurring number in the data set

In this case, the

Mode is 114

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Step-by-step explanation:

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find the value of x of given figure and solve this question step by step plzz help question number D

Alinara [238K]

Answer:

x=15 cm

Step-by-step explanation:

The two triangles in the diagram are:

ABC and BDC

First we have to find the third side (hypotenuse) of BDC so that we can use it to find the value of x.

Hypotenuse is the largest side of a triangle which is usually in front of the right angle.

So in BDC

$Base = BD =10cm\\Hypotenuse = BC = ?\\Perpendicular = CD = 2\sqrt{11}cm$

Applying Pythagoras theorem:

$(Hypotenuse)^2 = (Base)^2 + (Perpendicular)^2\\BC^2 = BD^2 + CD^2\\BC^2 = (10)^2 + (2\sqrt{11})^2\\BC^2 = 100+(2^2 * 11)\\BC^2 = 100+(4*11)\\BC^2 = 100+44\\BC^2 = 144\\\sqrt{BC^2} = \sqrt{144}\\BC = 12cm$

Solving for triangle ABC

$Base = BC = 12 cm\\Perpendicular = AB = 9 cm\\Hypotenuse = AC = x\\$

Applying Pythagoras theorem

$AC^2 = BC^2+AB^2\\x^2 = (12)^2 + (9)^2\\x^2 = 144+81\\x^2 = 225\\\sqrt{x^2} = \sqrt{225}\\x = 15cm$

Hence,

x=15 cm

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2 years ago