Answer:
Step-by-step explanation:
Answer:
f'(x) = -f(x) = 9xy² - 6x²y + 5x³
Step-by-step explanation:
f(x) = –9xy² + 6x²y – 5x³
additive inverse: f'(x) = -f(x) = 9xy² - 6x²y + 5x³
f(x) + f'(x) = f(x) -f(x) = (–9xy² + 6x²y – 5x³) + (9xy² - 6x²y + 5x³) = 0
Answer:
see explanation
Step-by-step explanation:
Given
A = 
bh
a. substitute b = 6 and h = 5 into the formula
A = × 6 × 5 = × 30 = 15 units²
b.
Multiply both sides of the formula by 2
2A = bh, that is
bh = 2A ← divide both sides by b
h = 
= 
= 
= 8
c
Using
bh = 2A ← divide both sides by h
b = 
= 
= 
= 6
0.55 can be converted to:
55/100
= 11/20
A point on the graph (for train b) that is exact is (2,250). From the origin, the rise is 250 and the run is 2. Rise/run would give us 250/2, which is 125. This means that train B travels 125mi every hour. For train A, we subtract the distance from hour 2 from hour 3 to get the miles per hour (because 3-2=1, subtracting the distance of hour 3 from 2 will give us the distance in 1 hour). 180-120= 60, meaning train A travels at 60mph. 60<125, meaning A
