Answer:
We have the problem:
|3r−15| if r<5
First we see the equality, if r = 5 we have:
I3r - 15I = I3*5 - 15I = I0I = 0.
Then the only restriction that we have is:
I3r - 15I > 0.
now, we could simplify it a bit further:
if r < 5, then the thing inside the absolute value will always be negative:
Then we can write:
I3*r - 15I = -(3*r -15) > 0
multiplying by -1 in both sides
(3r - 15) < 0.
if we keep simplifying this, we will get our initial restriction:
3r - 15 < 0
3r < 15
r < 15/3 = 5
r < 5
The probability is 9/16.
This is because in the simulation, 9 of the results had 2 or 3 girls, and there was a total of 16 choices.
Answer:
$6,237 down payment
Step-by-step explanation:
calculated 
×
%×
The right answer for the question that is being asked and shown above is that: "D. all real numbers less than or equal to 0." This is the statement that <span>best describes the range of the function f(x) = 2/3(6)x after it has been reflected over the x-axis</span>
<h3>
Answer: Choice A. 13 & 5/8 inches</h3>
Ideally you should always post the diagram to help us see the entire problem; however, the diagram is not needed in this case because we are told the figure is regular decagon. So there are 10 sides and each side is the same length. If each side is x inches long, then the perimeter is 10x inches.
10x = 136 & 1/4
10x = 136 + 1/4
10x = 136 + 0.25
10x = 136.25
x = 136.25/10
x = 13.625
x = 13 + 0.625
x = 13 + 625/1000
x = 13 + 5/8
x = 13 & 5/8
