The probabability of winning on at least 1 bet is equal to 1 less the probaility of not winning on either of the 6 bets.
The probability of not wining on any bet is independent of winning or not winning on any of the bets, so the combined probability is calculated as the product of each individual probability.
Each indivitual probability of not winning the is:
(number of not winning outcomes) / (number of possible outcomes) = 37 / 38.
Then, the combined probability of not winning the six times is: (1/38)*(37/38)*(37/38)*(37/38)*(37/38)*(37/38) =(37/38)^6
Therefore, the probability of winning at least one bet is:
= 1 - (37/38)^6 ≈ 1 - 0.973684 ≈ 0.03.
Answer: 0.03.
Well we already know that the 36:100 is correct because it is the starting amount, to check the 18:50 50 is half of the 100 insects so you would divide 36 by 2 which gives you half of 36 which is 18 so we can check off 18:50 as correct. Idk about the final one but the other two are correct.
The answer for your question question is 3+ 16/3 i
The graph of the linear equation can be seen in the image below.
<h3 /><h3>How to graph the linear equation?</h3>
Here we have the linear equation:
y = (2/5)*x - 6
To graph it, we just need to find two points on the line, and then connect them with a line.
To find the points we just evaluate in two values of x.
if x = 0.
y = (2/5)*0 - 6 = -6
Then we have the point (0, -6)
If x = 5.
y = (2/5)*5 - 6 = 2 - 6 = -4
Then we have the point (5, - 4)
Now we can graph these two points and connect them with a line. The graph of the line can be seen below.
If you want to learn more about linear equations:
brainly.com/question/1884491
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Answer:
The answer is "MS and QS".
Step-by-step explanation:
Given ΔMNQ is isosceles with base MQ, and NR and MQ bisect each other at S. we have to prove that ΔMNS ≅ ΔQNS.
As NR and MQ bisect each other at S
⇒ segments MS and SQ are therefore congruent by the definition of bisector i.e MS=SQ
In ΔMNS and ΔQNS
MN=QN (∵ MNQ is isosceles triangle)
∠NMS=∠NQS (∵ MNQ is isosceles triangle)
MS=SQ (Given)
By SAS rule, ΔMNS ≅ ΔQNS.
Hence, segments MS and SQ are therefore congruent by the definition of bisector.
The correct option is MS and QS