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2 years ago

A bag of fertilizer weighs 6 1/2 lb. How much does 1 1/3 bags of fertilizer?

Mathematics

1 answer:

stellarik [79]2 years ago

4 0

Answer:

8 2/3lbs

Step-by-step explanation:

6 1/2×1 1/3=6 3/6+2 1/6

=8 4/6= 8 2/3

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What is the slope or change of 6(x-y) =5(x+y)

scoundrel [369]

6x - 6y = 5x + 5y ; / - 6x
We solve for y ;
-6y = -x + 5y ; / -5y
-y = -x ; / *(-1) ;
y = 1*x ;
The slope is 1.

3 0

2 years ago

Daria invested $5,000 in an account that earns 5% interest annually. She will earn $(blank) in interest over nine months.

Murrr4er [49]

5000*.05. The answer is $250.

4 0

2 years ago

Explain the relationship between the polynomial identities: x^2 − 1 = (x +1)(x − 1) and x^2 − a^2 =(x − a)(x +a).

Bess [88]

Answer:

So these two equation can be related by identity $x^2-a^2=(x+a)(x-a)$

Step-by-step explanation:

We have given equation $x^2-1=(x+1)(x-1)$

And $x^2-a^2=(x+a)(x-a)$

We know the algebraic identity $a^2-b^2=(a+b)(a-b)$

From this identity

$x^2-1$ can be written as (x+1) (x-1)

And using same identity $x^2-a^2$ can be written as $(x-a)(x-b)$

So these two equation can be related by identity $x^2-a^2=(x+a)(x-a)$

5 0

2 years ago

Start with the geometric power series LaTeX: 1+x+x^2+x^3+x^4+\cdots Substitute LaTeX: -x^3in place of LaTeX: x, and then take a

valina [46]

Answer:

$-3x^2+6x^5-9x^8+12x^{11}+...=\sum_{n=1}^{\infty }\left ( -1 \right )^n\,\,3n\,\,x^{3n-1}$

Step-by-step explanation:

Given : $1+x+x^2+x^3+x^4+\cdots$

On putting $-x^3$ in place of x , we get $1+\left ( -x^3 \right )+\left ( -x^3 \right )^2+\left ( -x^3 \right )^3+\left ( -x^3 \right )^4+...$

On simplifying , we get $1-x^3+x^6-x^9+x^{12}+...$

On differentiating , we get $\left ( 1-x^3+x^6-x^9+x^{12}+... \right )'=-3x^2+6x^5-9x^8+12x^{11}+...$

Here ,

$-3x^2=\left ( -1 \right )^1\,3(1)x^{3(1)-1}\\6x^5=\left ( -1 \right )^2\,\,3(2)\,\,x^{3(2)-1}\\-9x^8=\left ( -1 \right )^3\,\,3(3)\,\,x^{3(3)-1}\\12x^{11}=\left ( -1 \right )^4\,\,3(4)\,\,x^{3(4)-1}$

Now , we need to express it using summation notation.

$\left ( 1-x^3+x^6-x^9+x^{12}+... \right )'=-3x^2+6x^5-9x^8+12x^{11}+...=\sum_{n=1}^{\infty }\left ( -1 \right )^n\,\,3n\,\,x^{3n-1}$

4 0

2 years ago

1) Find (10) in the sequence given by b(n) = -5+9(n - 1).<br> b(10) =

S_A_V [24]

Answer:

b(10) = 76

Step-by-step explanation:

To find b(10) substitute n = 10 into the formula

b(10) = - 5 + 9(10 - 1) = - 5 + 9(9) = - 5 + 81 = 76

8 0

2 years ago