Key terms: Reset Compounds that contain a carbon-carbon double bond are known as ____________ . Alkenes are electron rich; there
fore, simple alkenes do not react with ____________ or bases, but will react with ____________ or acids. In the IUPAC system, an alkene is identified by the suffix ____________ . Addition reactions in which two parts of a reagent are added to the same side of a double bond are known as ____________ additions. Addition reactions in which two parts of a reagent are added from opposite sides of a double bond are called ____________ additions. Halogenation and halohydrin formation occur with ____________ addition. Hydroboration occurs with ____________ addition.
Answer: Compounds that contain a carbon-carbon double bond are known as _____alkenes_______ . Alkenes are electron rich; therefore, simple alkenes do not react with _____nuceophiles_______ or bases, but will react with _____electrophiles_______ or acids. In the IUPAC system, an alkene is identified by the suffix _____-ene_______ . Addition reactions in which two parts of a reagent are added to the same side of a double bond are known as _____syn_______ additions. Addition reactions in which two parts of a reagent are added from opposite sides of a double bond are called _____anti_______ additions. Halogenation and halohydrin formation occur with _____anti_______ addition. Hydroboration occurs with _____syn_______ addition.
Explanation:
The right terms have been filled into the statement.
Electrophiles are election rich so they react with nucleophiles. And vice versa.
Addition reactions in which two parts of a reagent are added to the same side of a double bond are known as _syn reaction and that involving opposite is anti reaction.
The Halohydrin formation reaction involves breaking a pi bond and creating a halohydrin in its place. Halo = halogen and Hydrin = OH. This reaction takes place in water and yields an anti-addition reaction which follows Markovnikov's rule.
The balanced equation for the neutralisation reaction is as follows 2H₃PO₄ + 3Mg(OH)₂ --> Mg₃(PO₄)₂ + 6H₂O stoichiometry of H₃PO₄ to H₂O is 2:6 number of H₃PO₄ moles reacted - 0.24 mol if 2 mol of H₃PO₄ form 6 mol of H₂O then 0.24 mol of H₃PO₄ forms - 6/2 x 0.24 = 0.72 mol of H₂O therefore 0.72 mol of H₂O are formed