Answer:
0.34 m/s^2
Explanation:
force=mass × acceleration
400 =1200 × acceleration
acceleration=400/1200
=0.34 m/s^2
Answer:
115.3 is the direction of the vector. Just learned some physics to get this answer over the past 3 hrs
Answer:
They will not stop at same elevation
for v=10m/2 => h=5.1m
for v=20m/2 => h=20.4m
Explanation:
If we neglect the effects of friction in the calculations the energy if the system must be conserved. The car energy can be described as a combination of kinetic energy and potential energy:
The potential energy is due to the gravitational forces and can be describes as:
Where g is the gravitation acceleration, m the mass of the car, and h the elevation. This elevation is a relative quantity and any point of reference will do the work, in this case we will consider the base of the hill as h=0.
The kinetic energy is related to the velocity of the car as:
As the energy must be constant E will be always constant, replacing the expressions for kinetic and potenctial energy:
In the base of the hill we have h=0:
When the car stops moving we have v=0:
This two must be equal:
solving for h:
Lets solve for the two cases:
for v=10m/2 => h=5.1m
for v=20m/2 => h=20.4m
As you can see, when the velocity is the double the height it reaches goes to four times the former one.
Answer:
Zero
Explanation:
Impulse is defined as the change in momentum.
Impulse is also defined as the product of force and the time duration of application of the force.
In the given problem, since there is no motion in the vertical direction, therefore the velocity of the box along the vertical direction is zero. So, momentum of the box along the vertical is also zero.
Hence the change is momentum is also zero along vertical direction.
Thus the impulse delivered by the box is zero.